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weeeeeb [17]
2 years ago
15

A person is connecting heat trace cable on pipe at the jobsite. The cable he or she is using is rated 2.5 watts/foot. How many f

eet of this cable can be installed on a 120-volt/15-amp circuit?
Mathematics
1 answer:
maksim [4K]2 years ago
7 0

The length of the cable will be 6 feet which can be installed  120-volt/15-amp circuit.

<h3>What is an ampere circuit?</h3>

Ampere's circuital law states that “the line integral of the magnetic field surrounding closed-loop equals to the number of times the algebraic sum of currents passing through the loop.”

Here we have a cable rating of 120-volt/15-amp so if the 1-ampere circuit means 1 watt per foot cable will be used for the 1-ampere circuit.

A Total of the 15-ampere circuit means 15 watts needed so we are using 2.5 watts per foot.

\rm Length \ of\  Cable =\dfrac{15}{2.5}=6 \ \ foot

Hence the length of the cable will be 6 feet which can be installed  120-volt/15-amp circuit.

To know more about the ampere circuit follow

brainly.com/question/14233513

#SPJ1

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In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?
kotegsom [21]

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

                   In ΔWXY, ∠Y=90°

                        XW = 53

                         YX = 28

                        WY = 45

Step:1

             Ref the attachment,

             Given triangle XWY is right angled triangle.

             Trigonometric ratio's,

                              Cos ∅  = \frac{Adj}{Hyp}    

             For the given attachment, the trigonometric ratio becomes,

                              Cos ∅  = \frac{XY}{XW}.....................................(1)

             Let, ∠X = ∅

             Where, XY = 28

                         XW =  53

             Equation (1) becomes,

                                 Cos ∅  = \frac{28}{53}

                                 Cos ∅ = 0.5283

                                        ∅ = cos^{-1} (0.5283)

                                        ∅ = 58.109°

Result:

          The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

             

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