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kap26 [50]
3 years ago
12

Use the information from the previous problem. Assume that each of the above numbers occurs once except for 33, which occurs twi

ce, and 135, which occurs four times. Calculate the weighted average of this new list of numbers?a) 58.89b) 81.56c) 134.22d) 146.80
Mathematics
1 answer:
sattari [20]3 years ago
3 0

The question is not complete! Here is the complete question and its answer!

Question:

Compute the average of the following numbers: 17, 33, 45, 66, and 135.

a) 45.00

b) 59.20

c) 61.67

d) 74.00

Use the information from the previous problem. Assume that each of the above numbers occurs once except for 33, which occurs twice, and 135, which occurs four times. Calculate the weighted average of this new list of numbers.

a) 58.89

b) 81.56

c) 134.22

c) 146.80

Answer:

b) 59.20

b) 81.56

Step-by-step explanation:

Sum = 17 + 33 + 45 + 66 + 135

Sum = 296/5

Average = Sum/Total terms

Average = 59.2

Therefore, correct answer is (b) 59.2

Weighted Sum = 17 + 2(33) + 45 + 66 + 4(135)

or we can also write like this

Weighted Sum = 17 + 33 + 33 + 45 + 66 + 135 + 135 + 135 + 135

Weighted Sum = 734

Weighted Average = Weighted Sum/Total terms

Weighted Average = 734/9

Weighted Average = 81.56

Therefore, correct answer is (b) 81.56

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4 years ago
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Stephen &amp; Richard share a lottery win of £2950 in the ratio 2 : 3. Stephen then shares his part between himself, his wife &a
horsena [70]

Answer:

Stephen's wife got £354 more than his son.

Step-by-step explanation:

Given:

Amount of Lottery = £2950

Now Given:

Stephen & Richard share a lottery amount in the ratio 2 : 3

Let the common factor between them be 'x'.

So we can say that;

2x+3x=2950\\\\5x = 2950

Dividing both side by 5 we get;

\frac{5x}{5}=\frac{2950}{5}\\\\x = 590

So we can say that;

Stephen share would be = 2x =2\times 590 = \£1180

Now Given:

Stephen then shares his part between himself, his wife & their son in the ratio 3 : 5 : 2.

Let the common factor between them be 'y'.

So we can say that;

3y+5y+2y=1180\\\\10y=1180

Dividing both side by 10 we get;

\frac{10y}{10}=\frac{1180}{10}\\\\y=118

So Stephen's wife share = 5y = 5\times 118= \£590

And Stephen's son share = 2y=2\times118 =\£236

Now we need to find how much more her wife got then her son.

To find how much more her wife got than her son we will subtract Stephen's son share from Stephen's wife share.

framing in equation form we get;

Amount more her wife got than her son = 590-236 = \£354

Hence Stephen's wife got £354 more than his son.

3 0
3 years ago
PLZZZ HELP ME I DON'T GET THISq
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Answer:

Step-by-step explanation:

To distribute means to multiply everything outside the parenthesis with everything inside the parenthesis, so in this case 7x8 then 7(x) then 7x2 so that is equal to 56 + 7x + 14, so combine the 56+14 so we get 7x + 70.  I hope '7' is part of the problem and not the question number

8 0
3 years ago
Read 2 more answers
Question 7 (1 point)
Otrada [13]

Answer:

(6, 9) (3, 0)

Step-by-step explanation:

Solve for each option using the slope formula:

Slope formula:

m = y2 - y1 / x2 - x1

m = 4 - 5 / 1 - 4

m = -1/-3

m = 1/3

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m = 0 - 9 / 3 - 6

m = -9 / -3

m = 3

This has a slope of 3!

m = 0 - 0 / -6 - 3

m = 0/ -9

m = 0

This is not 3.

m = 2 - 1 / 0 - 3

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This is not 3.

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3 years ago
Sam purchased a video game for $24.99 but paid $28.56. Sam paid how much did sam pay in sales tax.
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28.56-24.99= $3.57
Sam payed $3.57 in sales tax.
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