<span>3 of the 20 toothbrushes are defective, so the initial probability of selecting a defective toothbrush on the first try is 3/20. After that, there will be 2 defective toothbrushes in the remaining 19, so the probability of selecting one of those on the 2nd try will be 2/19. To get the probability of those two events happening sequentially, we multiply the two probabilities. Thus (3/20)*(2/19) = 6/380 = 0.0157, or about 1.6%.</span>
Answer:
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Answer:
Step-by-step explanation:
Factor the numerator and cancel common factors from numerator and denominator.
Answer:
5.61×10^8 ton/day
Step-by-step explanation:
(2.08×10^5 ft³/s)·(8.64×10^4 s/day)·(6.24×10^1 lb/ft³)/(2×10^3 lb/ton)
= (2.08·8.64·6.24/2)×10^(5+4+1-3) ton/day
≈ 56.07×10^7 ton/day
≈ 5.61×10^8 ton/day
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We have expressed the answer using 3 significant digits, to match the precision of the rate and weight.
