Answer:
28.57% drop
Step-by-step explanation:
Number of runs
- Last year = 28
- This year = 20
Change this year:
Change %:
Answer:
- The function is injective but nor surjective
Step-by-step explanation:
<u>We see that:</u>
<u>For any x₁ and x₂ ∈ N, </u>
- f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers
It it confirmed one-to-one, hence it is injective
<u>Check the surjectivity:</u>
f(x) = y ∈ N
<u>Let y = 2, then:</u>
Since x is not natural, the function is not surjective
If a function is even, then f(-x) = x.
If a function is odd, then f(-x) = -x.
y = x³ + x² → f(x) = x³ + x² → -f(x) = -(x³ + x²) = -x³ - x²
f(-x) = (-x)³ + (-x)² = [(-1)(x)]³ + [(-1)(x)]² = (-1)³x³ + (-1)²x²
= -1x³ + 1x² =-x³ + x²
f(-x) ≠ f(x) and f(-x) ≠ -f(x)
y = x³ + x² is not odd and not even
Answer: neither
I’m pretty sure it’s linear!