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coldgirl [10]
2 years ago
14

Can someone help me on this ASAP? This is a PRACTICE test and i already know the answer which is A.

Mathematics
1 answer:
Over [174]2 years ago
5 0

Answer:

122 1/4

Step-by-step explanation:

Hope this helps! :)

(12x12) 12x \frac{2}{3\\} x12) / (3/2 x3/2)

PEMDAS = parathesis exponents multiplictation division add subtract.

12x12=24

3/2x3/2=9/4

12x2/3=8x12=96

so 24+96=120

9/4 can be like 4x2=8 so i remaing

120+2=122 1/4?

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Answer: 12 3/8 10 1/2 + 10 1/2= 21 45 3/4 - 21 = 24 3/4 24 ÷ 2 = 12 Change the 3/4 into 8ths = 6/8 Divide that in half which gives you 3/8 So the length is 12 3/8
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MARKING BRANLY You want to plant a flower garden in your yard so that you can make a beautiful bouquet to put on the alter at ch
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Answer:

1. 3 packs of daffodils and 4 packs of tulips

2. then you would have 24 of each

3. $2.29

4. $37.54

5. $34.61

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Step-by-step explanation:

3.   4.50*4=18            5.75*3=17.25

18+17.25 -> 35.25*.065=2.29 rounded

4. 35.25+2.29=37.54

5.  35.25-2.75->32.50*.065=2.11       2.11+32.50=34.61

6. 37.54-34.61=2.93

7. 6:8  -> 3:4  ratio -> 3:4

8. 8+4=12

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6 0
3 years ago
Which set of numbers could represent the lengths of the sides of a right triangle?
DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

<h3>Pair: 8, 15, 17</h3>

By the pythagorean theorem, a triangle is a right triangle if and only if

\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2.

In this case,

\text{longest side}^2 = 17^2 = 289.

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}.

In other words, indeed \text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2. Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

<h3>Pair: 10, 15, 20</h3>

Factor out the common factor 2 to simplify the calculations.

\text{longest side}^2 = 20^2 = 400

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}.

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 12, 18, 22</h3>

\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121.

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}.

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 7, 9, 11</h3>

\text{longest side}^2 = 11^2 = 121.

<h3>\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}.</h3>

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

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