Pls help correct asnwers only thx

Mathematics

2 answers:

il63 [147K]1 year ago

8 0

Answer:

$x\leq -8$

Step-by-step explanation:

1. Add -8 to both sides, which gives you $8x\leq -64$ , as -72 +8 = -64

2. Then, divide 8 from both sides, which gives you $x\leq -8$ .

Hope this helped.

Anton [14]1 year ago

3 0

It’s gonna be x >_ -8

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Guys i need your HELP ASAP

ivanzaharov [21]

To solve this, you’ll first need to solve for their slopes.

The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3

We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3

The equation you get it y = 1/3x + b.

Now you will need to solve for b by substituting in the first ordered pair of line R.

2 = 1/3(1) + b.

Once you solve for b, you should get 5/3 and y = 1/3x + 5/3

Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.

y = 1/3(10) + 5/3.

Your solution should be 5.

So your answer is: a = 5

8 0

3 years ago

(18x-44 )(8x-10) (13y-38) geometry

xenn [34]

Simplifying

18x + -44 = 13y + -38

Reorder the terms:

-44 + 18x = 13y + -38

Reorder the terms:

-44 + 18x = -38 + 13y

Solving

-44 + 18x = -38 + 13y