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Setler [38]
2 years ago
9

Write your answer as a

Mathematics
1 answer:
postnew [5]2 years ago
4 0
8 friends: 2 pounds of grapes.

Each friend get 1/4 a pounds of grapes.
You might be interested in
The product of two mixed numbers x and y is 10. If x= _ 2/3 and y=_ 3/4 ,<br> find x and y?
Akimi4 [234]

Answer:

  • x = 2 2/3
  • y = 3 3/4

Step-by-step explanation:

There may be other ways to do this. Here's the approach I took. Let the integer part of x be represented by "a", and the integer part of y be represented by "b". Now, we have ...

  (a +2/3)(b +3/4) = 10

Multiplying by 12, this becomes ...

  (3a +2)(4b +3) = 120

There are only 16 divisors of 120, so they can be easily enough checked one at a time.

  120 = 1·120 = 2·60 = 3·40 = 4·30 = 5·24 = 6·20 = 8·15 = 10·12

Of these divisors, the ones that are of the form 3a+2 are ...

  2, 5, 8, 20 . . . . a=0, 1, 2, 6

The ones that are of the form 4b+3 are ...

  3, 15 . . . . b = 0, 3

The factor pair that consists of a number on the first list and a number on the second list is ...

  120 = 8·15

corresponding to a=2 and b=3. So, the mixed numbers you want are ...

  x = 2 2/3

  y = 3 3/4

_____

<em>Check</em>

  (2 2/3)·(3 3/4) =2·3 +2·3/4 +2/3·3 +2/3·3/4 = 6 +6/4 +2 +2/4 = 8+8/4 = 10

6 0
3 years ago
Pls help I dont understand this
s2008m [1.1K]

Answer:

D

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
How many numbers are 10 units from zero on the number line
Amanda [17]
That would be 2 numbers. they are 10 and -10.
6 0
3 years ago
the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2
lilavasa [31]

Answer:  c) \dfrac{3}{2} .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}

Given function : f(x) = x^2

Interval : [0,3]

Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that

f'(c)=\dfrac{f(3)-f(0)}{3-0}\\\\=\dfrac{3^2-0^2}{3}=\dfrac{9}{3}\\\\=3

\Rightarrow\ f'(c)=3\ \ \ ...(i)

Since f'(x)=2x

then, at x=c, f'(c)=2c\ \ \ ...(ii)

From (i) and (ii), we have

2c=3\\\\\Rightarrow\ c=\dfrac{3}{2}

Hence, the correct option is c) \dfrac{3}{2} .

4 0
3 years ago
Megan took a cab ride and was charged a fare of $1.50 per mile and an additional charge of $5 for her luggage. If Megan traveled
____ [38]
For example let's say Megan has to pay the cab driver $50. Here's the equation 50=1.50x + 5 First you want to get x by itself on one side. So subtract 5 on both sides 50=1.50x + 5 -5 -5 --------------------------- 45=1.50x Now that you have x on one side; however, you want to divide to get the answer. 45=1.50x ----------------------- 1.50 x = 30 So if Megan pay $50 that mean she rode 30 miles ~by the way I'm sorry if you are looking at the answers and it isn't in the right place, I'm answering this on a tablet~
7 0
3 years ago
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