The polynomial functions in their expanded form is given as follows. It is right to state that there are no breaks in the domain of h(x).
<h3>
What is a polynomial function?</h3>
In an equation such as the quadratic equation, cubic equation, etc., a polynomial function is a function that only uses non-negative integer powers or only positive integer exponents of a variable.
For instance, the polynomial 3x+4 has an exponent of 1.
Part A: F(x) has zero at 2 and multiplicity of 1; and
1 at the multiplicity of 2
f(x) = x-2) (x-1)²
= (x-2) (x² - 2x + 1)
= x³ - 4x² + 5x -2
Part B: h (x) = ![\left \{ {{x^3 -4x^2 + 5x -2; X < 0} \atop {\sqrt[3]{x-2} ; X\geq 0 }} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%5E3%20-4x%5E2%20%2B%205x%20-2%3B%20X%20%3C%200%7D%20%5Catop%20%7B%5Csqrt%5B3%5D%7Bx-2%7D%20%3B%20X%5Cgeq%200%20%7D%7D%20%5Cright.)
The domain of X is X ∈ R
Hence it is correct to state that there are no breaks in the domain of h(x).
Learn more about polynomial functions:
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Answer:
-4/5
Step-by-step explanation:
Slope equation. Take 2 points from the graph and put them into this equation:
y2 and x2 are the second point on the graph (5, -1) and vice versa.
Answer:
(f-g)(x) = x^4 - x^3 - 4x^2 - 3
Step-by-step explanation:
(f-g)(x) = x^4 - x^2 + 9 - (x^3 + 3x^2 + 12)
(f-g)(x) = x^4 - x^2 + 9 - x^3 - 3x^2 - 12
(f-g)(x) = x^4 - x^3 - 4x^2 - 3
Use midpoints and bisectors to find the halfway mark between two coordinates. ... Midpoint Formula: For two points, (x1,y1) and (x2,y2),