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3 years ago

How do you solve for x with segment bisectors?

1 answer:

8 0

Use midpoints and bisectors to find the halfway mark between two coordinates. ... Midpoint Formula: For two points, (x1,y1) and (x2,y2),

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Help with num 4 please.

kati45 [8]

Answer:

y=1/2(x-1)

Step-by-step explanation:

If x=t^2 and t>0, then t=sqrt(x).

If t=sqrt(x) or x^(1/2) and y =1-1/t, then y=1-x^(-1/2).

The x-intercept is when y=0.

So we need to solve 0=1-x^(-1/2) to find point P.

Add x^(-1/2) on both sides: x^(-1/2)=1.

Raise both sides to -2 power: x=1

So point P is (1,0).

Let's find tangent line at point (1,0).

We will need the slope so let's differentiate.

y'=0+1/2x^(-3/2)

y'=1/(2x^(3/2))

The slope at x=1 is y'=1/(2[1]^(3/2))=1/(2×1)=1/2.

Recall point-slope form is y-y1=m(x-x1).

So our line we are looking for is y-0=1/2(x-1)

Let's simplify left hand side y=1/2(x-1)

4 0

3 years ago

Are there any verticals angles? If so name them.

tigry1 [53]

Answer:

No, there are no vertical angles shown.

6 0

3 years ago

Read 2 more answers

NEED DONE FAST GIVING 40 POINTS

dlinn [17]

To solve this problem you must apply the proccedure shown below:

1. The perimeter of a rectangle can be calculated with the following formula:

$Perimeter=2Width+2Length$

2. The width is:

$Tan\alpha=opposite/adjacent\\Tan(72)=12/W\\ W=(12)(Tan(72))\\ W=3.89 in$

3. Now, you must substitute the values into the formula for calculate the perimeter:

$Perimeter=2(3.89in)+2(12in)\\ Perimeter=31.78in$

Therefore, the answer is: $31.78 in$

7 0

3 years ago

Simplify: (8t4 + 6 )+(914 – 2ť + 6t? – 6 )

vekshin1

Answer:t

2⋅(17t 2 −2t+6)

Step-by-step explanation:

v(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

5 0

3 years ago

In a single-elimination tournament, half of the remaining teams are eliminated in each round. If the tournament starts with 128

Monica [59]

128/2 = 64
64/2 = 32
32/2 = 16
16/2 = 8
8/2 = 4
answer: 4

4 0

3 years ago