<span>2x^2 - 19x - 33 = 0 </span>
<span>The factors of 2 are 1 x 2. </span>
<span>The factors of 33 are 1 x 33 and 3 x 11. </span>
<span>Using Guess and Test and FOIL, find a combination that gives you a middle term of -19x: </span>
<span>(2x + 3)(x - 11) = 0. </span>
<span>Using the principal of zero product, solve each equation for x: </span>
<span>2x + 3 =0 and x - 11 =0. </span>
<span>The two solutions are x = -3/2 and x = 11.
</span>
Answer:
Mark brainliest please if i am correct one more brainliest please
Step-by-step explanation:
A=a+b
2h=15+25
2·5=100
Answer:
80
Step-by-step explanation:
720/P = 9/1
Cross multiply.
9P = 720
P = 720/9
P = 80
Standard form: Ax+By=C
first put in slope-intercept form:
slope = (0+5)/(6-3) = 5/3
pick point D: 0 = 5/3(6)+b -> b= -10
slope-intercept form: y=(5/3)x-10
multiply both sides by 3:
3y=5x-30
put in standard form:
5x-3y=30
Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
