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valentinak56 [21]
2 years ago
7

What is the value of each of these prefix expressions

SAT
1 answer:
BARSIC [14]2 years ago
7 0

The value of the given prefix expression *2 / 8 4 3 is calculated to be;  1

<h3>How to work with preorder transversals?</h3>

We are given the expression; *2 / 8 4 3

We will start from the rightmost operation symbol.

For every operation symbol, the two integers following the operation symbol are the symbols on which the operation needs to be performed. Then we replace the operation symbol with the two following integers by the result of the operation.

Then we repeat for the rightmost operation symbol in the remaining string.

*2 / 8 4  3

        8 / 4 = 2

⇒ *2 2 3

2 * 2 = 4

4 - 3 = 1

Thus the value of the prefix expression is then 1.

Read more about preorder transversals at; brainly.com/question/12947940

#SPJ1

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Present three incidences, as examples, where sport personalities right were violated
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The incidences are:

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<h3>How does racism influence participation in sport?</h3>

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7 0
2 years ago
Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetri
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The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

<h3>What is the standard error of the distribution?</h3>

The standard error of the distribution is calculated as follows:

  • Standard error = standard deviation/√N

where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

  • 68% of the data lies within one standard deviation
  • 95% percent within two standard deviations, and
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Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

One standard deviation = 175 - 190 or 205 - 190 = ±15

Standard deviation = 15

a. Solving for the standard error using the equation above;

Standard error = 15/√100

Standard error = 1.5

b. The range of 95% confidence interval is two standard deviations away from the mean.

Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

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