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2 years ago

Use the dots for one and two. what is the difference between the ranges

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

6 0

Answer:

a. 20 points

Step-by-step explanation:

Range = Largest given value - Smallest given value.

Identifying the range of test 1

Looking at the dot plot the lowest test grade appears to be 50 while the highest is 90.

So range of test 1 = 90 - 50 = 40

Identifying the range of test 2

Looking at the plot the lowest test grade appears to be 40 while the highest appears to be 100

So range = 100 - 40 = 60

Identifying the differences between the ranges

Test 1 range : 40

Test 2 range : 60

Difference between the two : 60 - 40 = 20 points

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Gwen volunteered to work at the ticket booth for her school's Halloween carnival. The chart below gives the number of hours Gwen

n200080 [17]

A linear relation is a relationship between two variables that when the corresponding pair of values of the variables are plotted, a straight line is obtained

The equation for the relationship between hours Gwen worked and number of tickets is t = 15·h

The reason the above equation is correct is as follows:

The given parameters are;

The table of values;

Hours(h): 1, 2, 3, 4

Tickets (t): 15, 30, 45, 60

Required: To write an equation that gives the relation between the number of hours Gwen worked and the number of tickets sold

Solution:

From the given table, we have;

The common difference between successive h-values is 1

The common difference between successive t-values is 30 - 15 = 45 - 30 = 60 - 45 = 15 = Constant

Given that the common difference of the h, and t-values are constant, the relationship is a linear relationship of the form, t = m·h + c

Where;

m = The rate of change of t with h, as follows;

m = (30 - 15)/(2 - 1) = 15

∴ t - 15 = 15 × (h - 1)

t - 15 = 15·h - 15

t = 15·h - 15 + 15 = 15·h

t = 15·h

The equation for the relation between the number of hours Gwen worked and the number of tickets she sold is t = 15·h

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3 years ago

What is thirty-five million, two hundred thousand, three in standard form?

Setler [38]

35,200,003 is the answer

6 0

3 years ago

Read 2 more answers

The distance from the centroid of a triangle to its vertices are 16cm, 17cm, and 18cm. What is the length of the shortest median

Marizza181 [45]

Answer:

$24$ $\text{cm}$

Step-by-step explanation:

Given: The distance from the centroid of a triangle to its vertices are $16\text{cm}$ , $17\text{cm}$ , and $18\text{cm}$ .

To Find: Length of shortest median.

Solution:

Consider the figure attached

A centroid is an intersection point of medians of a triangle.

Also,

A centroid divides a median in a ratio of 2:1.

Let G be the centroid, and vertices are A,B and C.

length of $\text{AG}$ $=16\text{cm}$

length of $\text{BG}$ $=17\text{cm}$

length of $\text{CG}$ $=18\text{cm}$

as centrod divides median in ratio of $2:1$

length of $\text{AD}$ $=\frac{3}{2}\text{AG}$

$=\frac{3}{2}\times16$

$=24\text{cm}$

length of $\text{BE}$ $=\frac{3}{2}\text{BG}$

$=\frac{3}{2}\times17$

$=\frac{51}{2}\text{cm}$

length of $\text{CF}$ $=\frac{3}{2}\text{CG}$

$=\frac{3}{2}\times18$

$=27\text{cm}$

Hence the shortest median is $\text{AD}$ of length $24\text{cm}$

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3 years ago

What is 2 3/5+ 1 4/5

Pavel [41]

Answer:

4 2/5

Step-by-step explanation:

7 0

3 years ago

A track star in Arizona ran the 100 meter dash event is six track meets. Her average time for all six meets was 11.8 seconds. Sh

natima [27]

Answer:

A track star in Arizona running time in the last meet was 11.5 seconds.

Step-by-step explanation:

Given:

average time for all six meets = 11.8 seconds.

Time for 1st meet = 11.7 seconds.

Time for 2nd meet = 11.6 seconds.

Time for 3rd meet = 12 seconds.

Time for 4th meet = 12.1 seconds.

Time for 5th meet = 11.9 seconds.

We need to find the running time for her last meet.

Solution:

Let the running time for her last meet be 'x'.

So we can say that;

average time for all six meets is equal to sum of Time for 1st meet, Time for 2nd meet, Time for 3rd meet,Time for 4th meet, Time for 5th meet and time for her last meet and then divided by 6.

framing in equation form we get;

$\frac{11.7+11.6+12+12.1+11.9+x}{6}=11.8\\\\\frac{59.3+x}6 =11.8$

Now Multiplying both side by 6 we get;

$\frac{59.3+x}{6}\times 6= 11.8\times6\\\\59.3+x=70.8$

Now Subtracting both side by 59.3 we get;

$59.3+x-59.3=70.8-59.3\\\\x=11.5 \ s$

Hence A track star in Arizona running time in the last meet was 11.5 seconds.

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3 years ago