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Darina [25.2K]
4 years ago
12

Its a simple RSM question that I can't get, please help WILL GIVE BRAINLIEST

Mathematics
1 answer:
Lesechka [4]4 years ago
3 0

Answer:

as a decimal, -22.33 as a fraction, -22 1/3

Step-by-step explanation: I showed my work so I hope that is correct

(REMEMBER P.E.M.D.A.S. STANDS FOR PARENTHESIS, EXPONENTS, MULTIPLY, DIVIDE, ADD, SUBTRACT-IN THAT EXACT ORDER)

first I would change the problem so that all of the fractions have the same common denominator and turn the mixed number into an improper fraction:

1.(75/100 / 3/100 - 2350/100)

second before solving anything else, I would solve inside the parenthesis with P.E.M.D.A.S. so I would solve 78/100 / 3/100

2. 78/100 / 3/100 =  26/100

now we have (26/100-2350/100) to solve in the parenthesis. I would make the denominator A LOT smaller before handling this.

3&4. 26/100 and 2350/100 both have common denominators of 50, 20,and 10. So you would get 13/50-1175/50, 26/20-470/20, or 26/10-235/10.

so 26/10-235/10= -235/10 also equal to -47/2 or -43.5 (-43 1/2)

so now we have (-47/2) / 1 1/2*2/3 + 1 1/6

I would continue following P.E.M.D.A.S. and add parenthesis around 1 1/2* 2/3 and solve (but first I would keep the same denominator)

5.1 1/2=3/2, 3/2=9/6 and 2/3 = 4/6

so, 9/6*4/6 = 36/36 which is equal to

now, we have (-47/2) / 1 + 1 1/6

and basically, we now have -47/2 + 7/6

which can be handled 2 ways

1/2,) turn to decimals, which looks like -23.5 + 1.17 (by rounding to the nearest tenths place) = -22.33

2/2,)simplify and subtract as fractions, which would look like -141/6 + 7/6 = -134/6 which is equal to -67/3 or as a mixed number, -22 1/3

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Answer:

0.6826 = 68.26% probability that the first machine produces an acceptable cork.

0.933 = 93.3% probability that the second machine produces an acceptable cork.

The second machine is more likely to produce an acceptable cork.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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What is the probability that the first machine produces an acceptable cork?

The first produces corks with diameters that are normally distributed with mean 3 cm and standard deviation 0.10 cm, which means that \mu = 3, \sigma = 0.1

Acceptable between 2.9 and 3.1, which means that this probability is the pvalue of Z when X = 3.1 subtracted by the pvalue of Z when X = 2.9.

X = 3.1

Z = \frac{X - \mu}{\sigma}

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X = 2.9

Z = \frac{X - \mu}{\sigma}

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For the second machine, we have that \mu = 3.04, \sigma = 0.04. Same probability we have to find out. So

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0.9332 - 0.0002 = 0.933

0.933 = 93.3% probability that the second machine produces an acceptable cork.

Which machine is more likely to produce an acceptable cork?

Second one has a higer probability, so it is more likely to produce an acceptable cork.

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