The astronauts of Expedition 28 on the international Space Station spend 15 weeks in space. Convert the time to minutes.

Mathematics

1 answer:

zzz [600]1 year ago

4 0

151,200 , this is because there are 10080 minutes in a week therefore you would times it by 15 , hope this helps :)

You might be interested in

Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point

a_sh-v [17]

A line parallel to y = 0.6x + 3 will be of the form:

$y = 0.6x + k$

where k is a constant.

It passes through (-3,-5)

Thus,

$y = 0.6x + k \\ \\ -5 = 0.6 \times (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2$

$\textbf{The equation is \: \: y = 0.6x - 3.2}$

3 0

2 years ago

A. 0 B. 1 C. 2 D. 3

zloy xaker [14]

-19 to -15 would be a positive 4 difference

19 to 15 = 4 this would be a -4 difference

3 to 7 is a positive 4 difference

-3 to 7 is a difference of 10

so there is 1 with a -4 difference
answer is B.

6 0

2 years ago

Subtract: 4x/x^2-25 - 2/x^2+2x-15

Alex777 [14]

Answer: $\dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

Step-by-step explanation:

Given

Subtract the expression

$\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$