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IgorC [24]
1 year ago
8

The astronauts of Expedition 28 on the international Space Station spend 15 weeks in space. Convert the time to minutes.

Mathematics
1 answer:
zzz [600]1 year ago
4 0
151,200 , this is because there are 10080 minutes in a week therefore you would times it by 15 , hope this helps :)
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100 cups of gasoline during a drive. he paid $3.12 per gallon for gas. How much did the gas cost?
Vanyuwa [196]
There are 16 cups in a gallon. Divide 100 into 16 to get 6.25. You now just multiply 3.12 by 6.25 to get 19.5. Your answer is $19.50.

hope this helps!
3 0
3 years ago
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There are 52 playing cards in a standard deck of cards. If Patrica selects a card at random, what is the probability that it wil
Alisiya [41]
Since there are two black queens out of 52 cards, there is a 2/52 chance of drawing a black queen first.  This is equivalent to a 1/26 chance.

Now that we have removed a black queen, there are 51 cards left in the deck.  26 of them are red because we only took away a black card.  This means that there is a 26/51 of drawing a red card next.

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8 0
3 years ago
What type(s) of symmetry does this figure have?
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It has reflectional symmetry
7 0
3 years ago
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What two numbers multiply to -8 and add to -4
Ronch [10]

Answer:

  -2-2√3, -2+2√3

Step-by-step explanation:

Let x represent one of the numbers. Then the other number is -4-x. We want the product to be -8:

  x(-4-x) = -8

  -4x -x^2 = -8 . . . . . eliminate parentheses

  x^2 +4x = 8 . . . . . . multiply by -1

  x^2 +4x +4 = 12 . . . add 4 to complete the square

  (x +2)^2 = 12

  x +2 = ±√12 = ±2√3

  x = -2±2√3

The two numbers are -2-2√3 ≈ -5.4641, and -2+2√3 ≈ 1.4641.

7 0
3 years ago
The average annual cost (including tuition, room, board, books and fees) to attend a public college takes nearly a third of the
Crazy boy [7]

Answer:

a) Private Colleges

Sample mean = 42.5 thousand dollars

Standard deviation = S1 = 6.62 thousand dollars.

Public colleges

Sample mean = 22.3 thousand dollars

Standard deviation = 4.34 thousand dollars

b) The difference in sample mean for both cases = 42.5 - 22.3 = 20.2 thousand dollars

The average amount of going to a Private college is 20.2 thousand dollars more than the average cost of going to public colleges

c) 95% confidence interval for a sampling distribution of the difference of the cost of private and public colleges is given as

(15.0, 25.4) thousand dollars.

Step-by-step explanation:

Private colleges.

52.8 43.2 45.0 33.3 44.0 30.6 45.8 37.8 50.5 42.0

Public colleges.

20.3 22.0 28.2 15.6 24.1 28.5 22.8 25.8 18.5 25.6 14.4 21.8

a) Calculate sample mean and standard deviation for both data set.

Mean = (Σx)/N

where N = Sample size

Σx = sum of all variables

Private colleges

Σx = (52.8+43.2+45.0+33.3+44.0+30.6+45.8+37.8+50.5+42.0) = 425

N = 10

Mean = 425/10 = 42.5 thousand dollars

Standard deviation = S1 = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = (52.8-42.5)² + (43.2-42.5)²

+ (45.0-42.5)² + (33.3-42.5)²

+ (44.0-42.5)² + (30.6-42.5)² + (45.8-42.5)² + (37.8-42.5)² + (50.5-42.5)² + (42.0-42.5)² = 438.56

N = 10

Standard deviation = √[Σ(x - xbar)²/N]

Standard deviation = √(438.56/10) = 6.62 thousand dollars

Public colleges

Mean = (Σx)/N

Σx =

(20.3+22.0+28.2+15.6+24.1+28.5+22.8+25.8+18.5+25.6+14.4+21.8) = 267.6

N = 12

Mean = (267.6/12) = 22.3 thousand dollars

Standard deviation = √[Σ(x - xbar)²/N]

[Σ(x - xbar)²

(20.3-22.3)² + (22.0-22.3)² + (28.2-22.3)² + (15.6-22.3)² + (24.1-22.3)² + (28.5-22.3)² + (22.8-22.3)² + (25.8-22.3)² + (18.5- 22.3)² + (25.6-22.3)² +(14.4-22.3)+(21.8-22.3) = 225.96

N = 12

standard deviation = s2 = √(225.96/12) = 4.34 thousand dollars

b) The difference in sample mean for both cases = 42.5 - 22.3 = 20.2 thousand dollars

The average amount of going to a Private college is 20.2 thousand dollars more than the average cost of going to public colleges.

c. Develop a 95% confidence interval of the difference between the annual cost of attending private and pubic colleges.

95% confidence interval, private colleges have a population mean annual cost $ to $ more expensive than public colleges.

To combine the distribution in this manner,

Sample mean of difference = 20.2 thousand dollars

Combined standard deviation of the sampling distribution = √[(S1²/n1) + (S2²/n2)]

= √[(6.62²/10) + (4.34²/12)] = 2.44 thousand dollars

Confidence interval = (Sample mean) ± (Margin of error)

Sample mean = 20.2

Margin of error = (critical value) × (standard deviation of the sampling distribution)

standard deviation of the sampling distribution = 2.44

To obtain the critical value, we need the t-score at a significance level of 5%; α/2 = 0.025

we obtain the degree of freedom too

The degree of freedom, df, is calculated in the attached image.

df = 15

t (0.025, 15) = 2.13145 from the tables

Margin of error = 2.13145 × 2.44 = 5.20

Confidence interval = (Sample mean) ± (Margin of error)

= (20.2 ± 5.2) = (15.0, 25.4)

Hope this Helps!!!

8 0
3 years ago
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