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r-ruslan [8.4K]
2 years ago
8

Determine whether the geometric series 1/54 + 1/9 + 2/3 + 4 + ... converges or diverges, and identify the sum if it exists.

SAT
2 answers:
maria [59]2 years ago
7 0

The geometric series 1/54 + 1/9 + 2/3 + 4 + ... diverges. The sum cannot tbe found.

<h3>What is geometric series?</h3>

A geometric series is the sum of an infinite number of terms that have a constant ratio between successive terms.

The given series is divergent type. The sum of any geometric series can be find out using the formula

S =a (1-r) where r is the common ratio. In this series, there is no common ratio.

Thus, the series is divergent and sum doesn't exist.

Learn more about geometric series.

brainly.com/question/4617980

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Dmitrij [34]2 years ago
5 0

Answer:

diverges

Explanation:

the answer is diverges

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In Europe, the themes that are emphasized through the paintings of Christmas include the following:

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In Visual art, a theme can be defined as a broad and deeper meaning that is being conveyed by a piece of artwork (painting). Thus, it is primarily related to the meaning and main purpose of an artwork (painting) rather than the subject.

Christmas is an annual event that is celebrated by Christians in remembrance of the birth of their lord and personal savior, who is Jesus Christ. Also, Christmas is generally celebrated across the world on the 25th of December of every year.

In Europe, the themes that are emphasized through the paintings of Christmas include the following:

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3 years ago
Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetri
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The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

<h3>What is the standard error of the distribution?</h3>

The standard error of the distribution is calculated as follows:

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where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

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  • 95% percent within two standard deviations, and
  • 99.7% within three standard deviations from the mean.

Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

One standard deviation = 175 - 190 or 205 - 190 = ±15

Standard deviation = 15

a. Solving for the standard error using the equation above;

Standard error = 15/√100

Standard error = 1.5

b. The range of 95% confidence interval is two standard deviations away from the mean.

Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL

In conclusion, the standard error is calculated from the standard deviation and the sample size.

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