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Allushta [10]
2 years ago
15

HELP DUE SOON EMERGENCY

Mathematics
1 answer:
algol [13]2 years ago
5 0

Answer:

The sum of the series is 44.

Step-by-step explanation:

Sigma notation. I just had a test on this, so this is pretty good timing.

Below the sigma, we see that k = 1. This means that 1 is the number you would substitute for k into the expression on the right to get the first term. In this case, the first term is -2. (2(1)² - 4)

Now, we can also find out the number of terms in the series by subtracting 1 (taken from k = 1) from the number on top of the sigma, 4, and then adding 1 to it.

4 - 1 + 1 = 4. This means there are 4 terms in the series.

See the remaining work in the attached file. You should get that the sum of the series is 44.

Hope this helps!

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7th question help please
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Surface area of the pyramid= 4*(area of the triangle) + area of the square

Area of the triangle = (1/2)*base*height=(1/2)*5*5= 25/2 in²
Area of the square = 5*5 =25 in²

Surface area of the pyramid = 4*(25/2) + 25=2*25 + 25=75 in²
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3 years ago
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Elderly drivers. In January 2011, The Marist Poll published a report stating that 66% of adults nationally think licensed driver
katrin [286]

Answer:

(a) Hence, the margin of error reported by The Marist Poll was correct.

(b) Based on a 95% confidence interval the poll does not provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65.

Step-by-step explanation:

We are given that the Marist Poll published a report stating that 66% of adults nationally think licensed drivers should be required to retake their road test once they reach 65 years of age.

It was also reported that interviews were conducted on 1,018 American adults, and that the margin of error was 3% using a 95% confidence level.

(a) <u>Margin of error formula is given by;</u>

             Margin of Error =  Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  

where, \alpha = level of significance = 1 - 0.95 = 0.05 or 5%

Standard of error =  \sqrt{\frac{\hat p(1-\hat p)}{n} }

Also, \hat p = sample proportion of adults nationally think licensed drivers should be required to retake their road test once they reach 65 years of age = 66%

n = sample of American adults = 1.018

The critical value of z for level of significance of 2.5% is 1.96.

So, <em>Margin of Error </em>=  Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  

                                =  1.96  \times \sqrt{\frac{0.66(1-0.66)}{1,018} } = 0.03 or 3%

Hence, the margin of error reported by The Marist Poll was correct.

(b) Now, the pivotal quantity for 95% confidence interval for the population proportion who think that licensed drivers should be required to retake their road test once they turn 65 is given by;

                   P.Q. =  \frac{\hat p-p}{ \sqrt{\frac{\hat p(1-\hat p)}{n} }}  ~ N(0,1)

So, <u>95% confidence interval for p</u> =  \hat p \pm \text{Margin of error}

                                                        =  0.66 \pm 0.03

                                                        =  [0.66 - 0.03 , 0.66 + 0.03]

                                                        =  [0.63 , 0.69]

Hence, based on a 95% confidence interval the poll does not provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65 because the interval does not include the value of 70% or more.

7 0
3 years ago
What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

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