First, you must find the width of GHJK. Since the area of it is 84m², divide 84 by 7.
84÷7=12
So the width of GHJK is 12m.
Next, find the scale of GHJK to LMNP. Since the height of both are already available, you can divide 21÷7 to get 3
This means that to get the width of LMNP you must multiply the width of GHJK by 3.
12×3=36.
Now, to get the area of LMNP, multiply 21 by 36.
21×36=756
So, the area of LMNP is 756m². (Don't forget the units!>
Answer:
a
Step-by-step explanation:
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
(B)Decreasing is the answer
1/2u - 3 x u
2u x u = 2u
answer 2u - 3