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3 years ago

Find all solutions of- 2r +4-8=0

Mathematics

1 answer:

mr_godi [17]3 years ago

4 0

Answer: -2

Step-by-step explanation: 4-8= -4 then it ends up being -2r-4=0

Then you add 4 to 0 so -2r=4 then divide

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Someone please help me. ASAP

guapka [62]

Answer:

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Step-by-step explanation:

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3 years ago

figure abcd is similar to figure mnkl if ab = 2x + 1, bc= 12, mn = 8, nk=7 and kl=13, what is the value of x

Kruka [31]

Step-by-step explanation:

are this form 1 question??

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3 years ago

Solve for x: 1/8-2/×=5 someone pls help me ASAP

cricket20 [7]

Begin by subtracting 1/8 from both sides to get $- \frac{2}{x} =5- \frac{1}{8}$ and get a common denominator of 8 on the right: $- \frac{2}{x} = \frac{40}{8} - \frac{1}{8}$ . Now simplify and cross-multiply: 39x = -16 andx = -16/39

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3 years ago

Two skiers are 30 kilometers apart and head towards each other. They meet in 2 hours. If the second skier is 5 kilometers per ho

DENIUS [597]

Answer:

Speed of first skier = 5 km/h

Speed of second skier = 10 km/h

Step-by-step explanation:

Given:

Distance between skiers = 30 km

Time after which they meet = 2 hours

Second skier is 5 km/h faster than the first skier.

To find speed of each skier.

Solution:

Let the speed of first skier be in km/h = $x$

Distance covered in km 2 hours will be = $Speed\times time=x\times 2=2x\ km$

Speed of second skier in km/h can be given as = $x+5$

Distance traveled by second skier after 2 hours will be = $Speed\times time=(x+5)\times 2=(2x+10)\ km$ [Using distribution]

Since, the skiers were 30 km apart initially, so the total distance covered by both of them when they meet after 2 hours will be = 30 km

Thus, we have:

$2x+2x+10=30$

Solving for $x$

$4x+10=30$

Subtracting both sides by 10.

$4x+10-10=30-10$

$4x=20$

Dividing both sides by 4.

$\frac{4x}{4}=\frac{20}{4}$

$x=5$

Speed of first skier = 5 km/h

Speed of second skier = $5+5$ = 10 km/h

8 0

3 years ago

What is m∠Q ?

ddd [48]

Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.

7 0

3 years ago

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Find all solutions of- 2r +4-8=0​

Find all solutions of- 2r +4-8=0