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astra-53 [7]
2 years ago
11

The points (3, 0) and (6, 9) fall on a particular line. What is its equation in slope-intercept form?

Mathematics
1 answer:
vekshin12 years ago
8 0

Answer:

(x2-x1)+(y2-y1)

Step-by-step explanation:

X2=0

X1=1

y2=9

y1=6

(0-1)+(9-6)

-1+3

2

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3 years ago
A study is conducted to determine how long a person will wait on hold on a telephone call before hanging up. A sample of 1000 pe
babymother [125]

Answer:

CI = ( 0,539 ; 0,599)

Step-by-step explanation:

The proportion p₀ of person that hung up the phone in the first minute of waiting is:

p₀ = 569/1000         p₀ = 0,569       p₀  =  56,9 %

Then q₀  = 1 - 0,569                          q₀  = 0,431       q₀ = 43,1 %

Sample size is  n = 1000

A 95 % CI  is:     α  = 5 %    α = 0,05      a/2 = 0,025

In z-table we look  z ( score ) for  0,025      z  = ± 1,96

Now CI for proportion is:

p₀ - z (α/2) * √ (p₀*q₀ )/n   < p < p₀ + z (α/2) * √ (p₀*q₀ )/n

we need to find out

z(α/2) * √ (p₀*q₀ )/n   =   1,96*√ ( 0,569*0,431)/1000 = 1,96 *0,01566 =0,03

Then

CI ( 95%) =  0,569 ± 0,03  =  ( 0,569 - 0,03 ;  0,569 + 0,03)

CI = ( 0,539 ; 0,599)

5 0
3 years ago
If f(x)=x/2+8, what is f(x) when x=10
MAVERICK [17]
F(X)=13 Just Plug 10 into the X in the equation

7 0
3 years ago
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The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected
mr Goodwill [35]
We have that if we assume standard exponential growth, the equation of the population will be:7000*e^{kt} if we start counting from the moment that the population was 7000. We are given that 7000* e^{5k}=12000, namely that P(5)=12000 and we need to find 7000e^{(5+5)k}=7000e^{10k}. Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000\frac{12000^2}{7000^2}= 20571 people.
3 0
3 years ago
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