Since it's so nicely grouped, we can work with it! For the equation to equal 0, x=0, 3, or -1 (since x-3 and x+1 equal 0 when plugged in with 3 and -1 respectively). All we have to do is plug in numbers before, between, and after these numbers and apply it to the rest of them. Since -1 is the smallest number of the group, we can plug in a number below that (for this example, -5) and plug it in to get -8*-5*-4= something negative since it contains an odd number of negative numbers. Therefore, anything less than 1 is negative. For between -1 and 0, we get x=-0.5 equals -0.5*-3.5*0.5=something positive (since it has an even amount of negative numbers), proving that everything between -1 and 0 here is positive. For something between 0 and 3, we can plug 1 in to get 1*-2*2= something negative. Do you see a pattern here? It's negative, then positive, etc.. Therefore, if the number is greater than 3 it is positive. Reviewing a bit, we can see that (-inf, -1) is negative as well as (0,3), making the interval notation (-inf, -1) U (0, 3) since when you plug -1, 0, and 3 in it is 0, not less than 0!
Answer:
-8
Step-by-step explanation:
First, plug in the numbers to the equation:
Any non-zero expression raised to the power of 0 equals 1:
Multiply the numbers:
-8
Hope this helped!
If you have to write the equation then it would be "5k + 6.7"
Answer:
Terms are the things that are separated by a (+) or a (-).
Step-by-step explanation:
<u>16x^3</u> - <u>4x^2</u> -4x+1
I don't think I'm right...
Answer:
-0.399
Step-by-step explanation:
f^-1(1024)=(2*1024-2/5)^-1= 0.000488
f(0.000488)=2*0.000488-2/5= -0.399
