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pantera1 [17]
3 years ago
7

if 5 billion pennies are minted each year, how long would it take to mint the pennies needed to stack to the sun? pls show all w

ork
Mathematics
1 answer:
antoniya [11.8K]3 years ago
5 0

Answer:

27591599.

Step-by-step explanation:

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10+3k=22 solve for k
defon
10+3k=22
-10 | -10
3k | 12 /3
=4

| k=4

5 0
4 years ago
A relief worker needs to divide 810 bottles of water and 324 cans of food into boxes that each contain the same number of items.
Likurg_2 [28]

Answer:

the largest number of relief supply that can put in a box is  T  =7

Step-by-step explanation:

From the question  we are told that

     The number of bottles to divide is n =  810 \ bottles

       The  number of  cans of food is m =  324 \ cans

 

First we need to find the Highest common factor of 810  and  324

Applying the Euclid algorithm(This method involves subtracting the difference from the smallest number till the differerence is zero  )

   We have  

            810 -324 * 1  =486

            486 - 324  *  1 = 162

              324 -162  * 1 = 162

               162 -162 * 1 = 0

 Thus the HCF is  162

So the maximum number of boxes is  z =  162 boxes

   The number of bottles of water in each box is  k = \frac{810}{162} =  5 \ bottles

    The number of  cans of food in each box is y =  \frac{324}{162}  = 2 \ cans

 Thus the largest number of relief supply that be put in the box is  

            T  =  k+ y

            T  = 5 + 2

            T  =7

4 0
3 years ago
X<br>ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
frosja888 [35]

Answer:

Ghww wt

Step-by-step explanation:

6h8d dgs gc

5 0
3 years ago
I can't figure out the question!!
Mars2501 [29]

Answer:

5in

Step-by-step explanation:

If 1in=210 you just divide 1050 by 210 and you get 5, so your answer is 5in.

I hope this helps :)

5 0
3 years ago
I need help with #9 and plz show work :)
earnstyle [38]

Answer:

\large\boxed{q=\dfrac{1-pr}{p}}

Step-by-step explanation:

p(q+r)=1\qquad\text{use the distributive property}\\\\pq+pr=1\qquad\text{subtract}\ pr\ \text{from both sides}\\\\pq=1-pr\qquad\text{divide both sides by}\ p\neq0\\\\q=\dfrac{1-pr}{p}

6 0
4 years ago
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