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3 years ago

Drag each tile to the correct box.

Mathematics

1 answer:

Gwar [14]3 years ago

3 0

Step-by-step explanation:

6x - 15 = 75, 6x = 90, x = 15.

2(2x - 1) = 46, 2x - 1 = 23, x = 12.

x + (x - 10) = 26, 2x = 36, x = 18.

5x - 3x = 10, 2x = 10, x = 5.

Hence the equations

in increasing order of x-values are:

5x - 3x = 10,

2(2x - 1) = 46,

6x - 15 = 75, and

x + (x - 10) = 26.

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If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
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\mathsf{-x=-8}\\\\
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I hope this helps. =)

Tags: rational equation fraction solution algebra

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