I can’t see good this image
Answer:

Step-by-step explanation:
Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)
This gives us the fraction: 
We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction: 
Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:
which can be simplified in exponent form as:
, now all we have to do is divide the 24 by the 3, to get 8
This gives us the answer: 
Step-by-step explanation:
<h3>• C. P = Cost Price.. , S. P (Sell Price) , </h3>
<h3>→ C.P = 100×S.P/100+Profit (when profit) </h3>
<h3>(a) C.P = 100 × 55/100 + 10 = 5500/110 </h3>
<h2> C.P » $ 50</h2><h3 /><h3 /><h3>(b) C.P = 100 × 558/100+24 = 55800/124 </h3>
<h2> C.P » $ 450</h2><h3 /><h3 /><h3 /><h3 /><h3 /><h3>→ C. P = 100 × S.P/100 - loss (when loss) </h3>
<h3> (c) C. P = 100 × 680 / 100 - 15 = 68000/85</h3>
<h2> C. P » $ 800</h2>
<h3>(d) C. P = 100 × 11.78 / 100 - 5 = 1178/95 </h3>
<h2> C. P » $ 12.4</h2>
Answer:Fred has 13 9/10 minutes left for question C
Step-by-step explanation:
The total time that Fred has to do the three-problem quiz is 30 minutes.
He spent 10 7/10 minutes on question A. Converting 10 7/10 minutes to improper fraction, it becomes 107/10 minutes.
He spent 5 2/5 minutes on question B. Converting 5 2/5 minutes to improper fraction, it becomes 27/5 minutes.
Total time that Fred spent on question A and question B is
107/10 + 27/5 = (107 + 54)/10
= 161/10 minutes.
The amount of time that he has left for question C would be
30 - 161/10 = (300 - 161)/10 = 139/10
= 13 9/10 minutes
Answer:
If you know two number a and b and need find, b is what percentage of a, P=b
- 100%
a