The first one : -6
the second : -14
Step-by-step explanation:

Using the zero product property you can set each expression equal to 0 (or factor for some of them)
All you have to do is set them equal to zero and simplify to solve for x
a. (x+13)=0
x= -13
(x-7)=0
x=7
b. (2x+3)=0
x=-3/2
(3x-7)=0
x=7/3
c. x=0
(x-3)=0
x=3
d.

needs to be factored
factor out an x to get:
x(x-5) and set each equal to 0
x = 0
(x-5)=0
x=5
e.

also needs to be factored
(x-7)(x+5)=0
(x-7)=0 (x+5)=0
x=7 x=-5
f.

Also needs to be factored using the ac method:



(3x-1)=0
x=1/3
(x+5)=0
x=-5
I hope this helps! (if so, give brainliest please!!)
24 weeks is the time it will take Kenny to take 132 quizzes
Answer:
(x - 2) and (x + 3) is a factor of: 2x² + 2x - 12
Step-by-step explanation:
2x² + 2x - 12 given equation
Now divide it by 2 we get,
x² + x - 6
then
x² + x - 6
x² + 3x - 2x - 6
x(x + 3) - 2(x + 3)
<em><u>(x - 2) (x + 3)</u></em>