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2 years ago

14

In a bin, there are 12 peppers: 2 red, 4 yellow, and 6 green. Without looking, a chef takes out a pepper. What is the probabilit

y of getting a yellow pepper

2 answers:

xz_007 [3.2K]2 years ago

8 0

The probability of getting a yellow pepper is 4/24 but, 1/6 if simplified.

zubka84 [21]2 years ago

8 0

4/24 of getting a yellow pepper if they are asking to simply 1/6

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Suppose a jar contains 18 red marbles and 38 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same

netineya [11]

Answer: 0.0993

Step-by-step explanation:

Since the jar contains 18 red marbles and 38 blue marbles, the total marbles will be:

= 18 marbles + 38 marbles

= 56 marbles

When 2 marbles are pull out at random at the same time, the probability that both are red will be:

= (18/56) × (17/55)

= 0.3214 × 0.3091

= 0.0993

4 0

3 years ago

ACT mathematics score for a particular year are normally distributed with a mean of 27 and a standard deviation of 2 points.

mel-nik [20]

Answer:

A: 16%

B: 95%

C: 97.5%

Step-by-step explanation:

According to the empirical rule:

68% of a normal distribution is between -1 and +1 standard deviations.

95% of a normal distribution is between -2 and +2 standard deviations.

99.7% of a normal distribution is between -3 and +3 standard deviations.

Given μ = 27 and σ = 2.

Part A

29 is one standard deviation above the mean. We can show this by calculating the z-score:

z = (x − μ) / σ

z = (29 − 27) / 2

z = 1

We know that 68% is between -1 and +1 standard deviations. Since normal distributions are symmetrical, we can also say that 34% is between 0 and +1 standard deviations.

P(0 < Z < 1) = 68%/2 = 34%

We can also say that 50% is less than 0 standard deviations.

P(Z < 0) = 50%

Therefore, P(Z < 1) = 34% + 50% = 84%.

Which means P(Z > 1) = 100% − 84% = 16%.

Part B

Like before, calculate the z-scores:

z₁ = (23 − 27) / 2

z₁ = -2

z₂ = (31 − 27) / 2

z₂ = 2

From the empirical rule, we know this is 95% of the normal distribution.

Part C

We found in part B that the z-score is 2.

P(0 < Z < 2) = 95%/2 = 47.5%

P(Z < 2) = 50% + 47.5% = 97.5%

5 0

4 years ago

a square has a side length of 18 feet. the square was dilated by a scale factor of 1/2 to create a new square. what is the side

dexar [7]

The side length of the new square would be 9. When you dialate you multiply by the square factor, so 1/2 times 18 equals 9.

8 0

4 years ago

Read 2 more answers

What is 5.6 as a fraction or mixed number in simplest form

kherson [118]

It would have to be 5 60/100

(5 wholes and sixty out of a hundred)

4 0

4 years ago

Read 2 more answers

Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p

scZoUnD [109]

Answer:

The probability that they will teach different courses is $\frac{2}{3}$ .

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Compute the probability that they will teach different courses as follows:

$P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}$

Thus, the probability that they will teach different courses is $\frac{2}{3}$ .

3 0

3 years ago