You need at least 2 congruent angles , or 3 proportional sides , or 2 proportional sides and 1 congruent angle to prove that 2 triangles are similar.
I presume that there should be a picture attached to this question , but if you only have 1 side in proportion ( x ) , you cannot prove the similarity of two triangles.
But if there already were two proportional sides or 1 proportional side and one congruent angle , you can prove they are similar if x = 48
Hope it helps
I can’t readdddddddddddddddd send it back
Answer:
dy/dt = y ( 3 - y )
Step-by-step explanation:
Given data:
Determine an autonomous differential equation with the following properties
y = 0 and Y = 3
y' > 0 for 0 < y < 3
y' < 0 for -∞ < y < 0 and 3 < y < ∞
considering an autonomous differential equation
dy/dt = y ( 3 - y )
y = 0 and 3 represents equilibrium solutions
if 0 < y < 3 then y ( 3 - y ) > 0 for 0 < y < 3
hence : dy / dt = y' > 0 for 0 < y < 3
y ( 3 - y ) < 0 for -∞ < y < 0 and 3 < y < ∞
hence : dy / dt = y' < 0 for -∞ < y < 0 and 3 < y < ∞
this shows that the autonomous differential equation satisfies every condition hence the autonomous differential equation is :
dy/dt = y ( 3 - y )
Answer:
5b i think
Step-by-step explanation:
Answer:
the answer would involve numbers
Step-by-step explanation:
