2/3(6c+4)-(8c-5)
1) Get rid of the negative signs
New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
2) Use distributive property for the first part by multiplying 2/3*6c= 4c and 2/3*4= 2 2/3
New equation: 4c+2 2/3+ (-8c) + 5
3) Combine like terms: 4c+(-8c)= -4c and 2 2/3+5= 7 2/3
New and simplified equation: -4c+ 7 2/3
Hello!
**Process pictured below**
When dividing, find how many times the first time in the divisor (2x + 3) fits into the first time of the dividend (2x³ + 5x² - 3x - 5). In this step, it fits x² times.
Multiply x² by the terms in the divisor and subtract from the dividend. Bring down the next term in the dividend to continue the process.
Repeat this step until you reach the last number. In this case, there was a remainder of 4. In order to write the remainder, you must express it over the divisor which makes it 4 / 2x + 3.
okay lets foces on question 20. 3/20
all you need to do is times the dinominator into 100 so 20x5=100 and now you have to multipy the same number that you multiplyed the first one by so 3x5=15 so the anwer would be 15/100 and to put that in a decimal you need to see the number on top witch is 15 so your real ANWSER IS .15
The square root of 225 is 15 :)