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3 years ago

The average rate of change of f(x)=3x+9 is 9. true or false?

1 answer:

7 0

The rate of change is the slope.
f(x) is the same as y...
f(x) = 3x + 9.....y = 3x + 9....and in y = mx + b form, the rate of change(slope) can be found in the m position.

y = mx + b
y = 3x + 9....so the slope or rate of change is 3...not 9...so answer is false

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Can someone help me with this?

baherus [9]

Answer:

Step-by-step explanation:

AB = AW + WB

But AW also equals WB because of the bisecting point

x + 6 = 3x

6 = 2x

x = 3

AW = 3 + 6 = 9

WB = 3(3) = 9

9 + 9 = 18°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0

3 years ago

Please help! I get how to do the first part I just don't get how to do the second part.

xz_007 [3.2K]

9514 1404 393

Answer:

WX = 33

(x, y) = (2, 10)

Step-by-step explanation:

The hash marks tell you WX is a midline, so has the measure of the average of the two bases.

WX = (PQ +SR)/2 = (27 +39)/2 = 66/2

WX = 33

The hash marks also tell you ...

PW = WS

y +4x = 18 . . . . . . substitute the given expressions

and also

QX = XR

2y +x = 22 . . . . . substitute the given expressions

If you solve the first equation for y, you get ...

y = 18 -4x

Substituting that into the second equation gives ...

2(18-4x) +x = 22

36 -7x = 22 . . . . . . . simplify

14 = 7x . . . . . . . . . . . add 7x-22 to both sides

2 = x . . . . . . . . . . . . divide by 7

y = 18 -4(2) = 10 . . . find y using the above relation

The values of x and y are 2 and 10, respectively.

My favorite "quick and dirty" way to solve a set of linear equations is using a graphing calculator. It works well for integer solutions.

7 0

3 years ago

Need this answered ASAP

White raven [17]

Answer:

10 1/8 years?

I hope this is right!

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

Can anyone help me plz

Kryger [21]

Answer:Ok

You need to get x by itself.

8x + c = k

Subtract c.

8x = k - c

Divide 8 from both sides.

x = k - c / 8

So, I believe it is D

Step-by-step explanation:

4 0

3 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

3 years ago