<span>If you would like to
know how many of each did Jan buy, you can calculate this
using the following two equations:
b ... the number of books
m ... the number of magazines
$16 = b * $3 + m * $2.50 ... 16 = 3 * b + 2.50 * m
b + m = 6 ... b = 6 - m
__________________
</span>16 = 3 * b + 2.50 * m
<span>16 = 3 * (6 - m) + 2.50 * m</span>
16 = 3 * 6 - 3 * m + 2.50 * m
16 - 18 = - 3 * m + 2.50 * m
- 2 = - 0.50 * m /0.50
m = 2 / 0.50
m = 4 magazines
<span>b = 6 - m = 6 - 4 = 2 books</span>
Result: Jan bought 4 magazines and 2 books.
Given
A tea that is 22% jasmine is blended with a tea that is 13% jasmine
Find out the how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
To proof
Let us assume that the a tea that is 22% jasmine is blended = a
Let us assume that the a tea that is 13% jasmine is blended = b
Total amount of tea made = 10lb
the equation be
a + b = 10
as given
jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
write 22% in the decimal form
= 0.22
write 13% in the decimal form
= 0.13
write 19.3% in the decimal form
= 0.193
than the equation be
0.22a + 0.13b = 0.193 × 10
on simplify
22a + 13b = 193
two equation becomes
22a + 13b = 193 and a + b = 10
multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193
we get
22a - 13a + 13b -13b = 193 - 130
9a = 63
a = 7lb
put this value in the a + b = 10
we get
7 + b = 10
b = 3lb
Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .
Hence proved
Answer:
Choice A is correct
Step-by-step explanation:
The distribution for town A is symmetric, but the distribution for town B is negatively skewed. From the box plots it is clear that the tails of the box plot for town A are equal in length while for town B the left tail is longer implying a negatively skewed distribution.
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
