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kozerog [31]
2 years ago
7

Bunco is a dice throwing game that requires no decisions to be made or skill on the part of the player just luck. In the simples

t form of the game there are six rounds, progressing in order from one to six, where the number of the round serves as the target for that round's rolls. Within a round, players alternate turns rolling three dice aiming to obtain the target number. Players gain one point for each die matching the target. If the player gets three-of-a-kind of the target number (a Bunco), they get 21 points. Write a program to simulate two players playing a round of Bunco showing the dice throws and scores during the games as well as the final scores and the player with the highest score. Also indicate which winner won the most rounds
Computers and Technology
1 answer:
anygoal [31]2 years ago
8 0
Abcdefghijklmnopqrstuvwxyz now I know my abcs, next time won’t you sing with me :)
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I Need an experienced or inspired game developer to answer these questions
Ivahew [28]

Answer:

WHAT ARE u trying to work for dm me on discord RealFazeRug#4361 and ill help ya m8 because im good with tech lol

Explanation:

5 0
4 years ago
Was LDAP version2 an internet standard in 1998? is it now?
mamaluj [8]

Answer Explanation:

LDAP stand for lightweight directory access protocol 389 is its port number it is an application layer protocol it was first invented in march 1998 and become very popular widespread  internet standard in august 1998 its authentication method is very simple the client send user name and password to LDAP server to access this.

4 0
3 years ago
2.3 Code Practice: Question 3
Tpy6a [65]

Answer:

Code in C++

Explanation:

C++ Code

#include<iostream> //for input and output  

using namespace std;  

int main()  

{  

  int hour;

  int minute;

  cout<<"Enter the hour:";

  cin>> hour;

  cout<<"Enter the minute:";

  cin>>minute;

  minute = minute+15;

  if(minute>=60){

   hour++;

   minute=minute-60;

  }

  if(hour>=24){

   hour=0;

  }

  cout<<"Hours: "<<hour<<endl;

  cout<<"Minutes:"<<minute;

  return 0;  

}

Code Explanation

First we need to declare two int variables to hold hour and minute values input from user.

Check if by adding 15 minutes into minute entered by user is greater then or equal to 60 then increment into hour and subtract 60 from minute.

Another check is that if user enters more then 24 hour or by making increment into hour, the hour values i greater then or equal to 24 then we need to change the hour to 0.

Result

Case 1:

Enter the hour:8

Enter the minute:15

Hours: 8

Minutes:30

Case 2:

Enter the hour:9

Enter the minute:46

Hours: 10

Minutes:1

8 0
3 years ago
(5 points) Create a user-defined data structure (i.e., struct) called Point that represents a two-dimensional Cartesian coordina
Harlamova29_29 [7]

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

#include <math.h>  //to use sqrt and pow function

#include<iomanip>  //to use setprecision

using namespace std;   //to identify objects cin cout

struct Point  {  // structure name

float x,y;  // member variables

};  

float calculateDistance (Point a, Point b)  {  //function that that takes two parameters of type Point

float distance;  //stores the distance between two points

distance=sqrt(pow(a.x-b.x,2)+pow(a.y-b.y,2));  //formula to compute distance between two points

return distance;  }  //returns the computed distance

int main()  {  //start of main function

Point p1,p2;  //creates objects of Point

cout<<"Enter point 1 coordinates: "<<endl;  //prompts user to enter the value for coordinates of first point

cin>>p1.x;  //reads input value of x coordinate of point 1 (p1)

cin>>p1.y;  //reads y coordinate of point 1 (p1)

cout<<"Enter point 2 coordinates: "<<endl;  //prompts user to enter the value for coordinates of second point

cin>>p2.x;  //reads input value of x coordinate of point 2 (p2)

cin>>p2.y;  //reads y coordinate of point 2 (p2)

cout<<"The distance between two points is "<<fixed<<setprecision(2)<<calculateDistance(p1,p2);} //calls function by passing p1 and p2 to compute the distance between p1 and p2 and display the result (distance) up to 2 decimal places

Explanation:

The program has a structure named Point that represents a two-dimensional Cartesian coordinate (x, y). The member variables of this struct are x and y, which are both floating-point values. A function called calculateDistance takes two parameters, a and b of type Pointer and returns the distance between the two given points using formula:

\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

It uses pow function to compute the power of 2 and sqrt function to compute the square root.

Then in main() method the program prompts the user to enter coordinates for two points and calls calculateDistance method to compute the distance between two points and display the result up to 2 decimal places using setprecision(2).

The program along with the output is attached in a screenshot.

6 0
3 years ago
Which of the following best describes professional behavior in the IT field?
Ray Of Light [21]
Answer - teaching others about technology in order to increase IT knowledge in the community
4 0
3 years ago
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