Answer: cost of 1 pot of ivy = $12
Cost of 1 rose bush =$ 10
Step-by-step explanation:
Step 1
Let rose bushes be represented as r
and pot of ivy be represented as p
such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as
7 r + p = 82----- eqn 1
Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as
5r +2 p = 74----- eqn 2
Step 2
Solving
7 r + p = 82----- eqn 1
5r +2 p = 74----- eqn 2
By elimination method Multiply eqn 1 by 5 and eqn 2 by 7
35r+ 5p= 410--- eqn 3
35r+ 14p =518--- eqn 4
Subtracting eqn 4 from eqn 3
9p = 108
p = 108/9
p=12
p = pot of ivy = $12
therefore rose bush wll be ( from equation 1)
7r+ p= 82
7r=82-12
7r= 70 r= 70/7
r= rose bush =$ 10
9514 1404 393
Answer:
1/8
Step-by-step explanation:
The fraction of the total is ...
(1/6) of (3/4) = (1×3)/(6×4) = 3/24 = 1/8
1/8 of the total garden is carrots.
Using properties of logarithms:
log(m+n) = log(m.n)
log(m-n) = log (m/n)
we get,
log(32x16/64)
On simplifying:
log(8)
and 8= 2^3
therefore,
log(2^3)
again using another property for exponents in logarithms we get:
3 log 2 <---- Answer
To solve this problem, you must find a common denominator. First, you multiply the denominators together, then, multiply the numerator of the first fraction by the original denominator of the second fraction and vis-versa.
3*4 = denominator of both
2*4 = numerator of first fraction
3*3 = numerator of second fraction
Your fractions should end up being 8/12 cups of raisins and 9/12 cup of almonds. You can now compare these fractions.
Overall, there are 1/12 more almonds than raisins.
