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lapo4ka [179]
3 years ago
14

How do you solve problem with two variables

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:


In your equations, there is only one variable you're using: y. I do not know what you mean by 2 variables, but probably you copied the wrong equations.  

......Anyways......  

To solve it, you must know that the sum of all 3 angles of a triangle is 180°.  

To set up the equation, add all three angle measures on one side of the equation, and then 180 on the other side. It should be like this:  

(6y+1)+(4y-7)+(9y+3) = 180  

Now that you're done with the set-up, I assume you know what to do next. We can't always do the work for you. ^_~  

> Add up the measures of each angle.  

> Isolate the equation with only variable on one side and only number on the other side.  

> Substitute each variable y for each angle measure and solve it.  

Hope this helps a lot. ^_^


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Answer:

<u>t = t₀ - 3n</u>

Step-by-step explanation:

Let t be the temperature and t₀ be the initial temperature of the day

Let n be the number of hours after the initial temperature ( t₀) was registered

Let -3 be the constant of change of temperature ( In 4 hours it went down 12 degrees)

Now, let's write down the expression that shows the temperature change each hour, this way:

t = t₀ - 3n

After 2 hours

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After 5 hours

t = t₀ - 3 * 5 = t₀ - 15

After 3 hours and 30 minutes

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a) \frac{8}{9} =0.89

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we know that

P(║ x -\mu║ \leq  k\sigma) \geq 1 -\frac{1}{k^2}

so, \mu = 150, \sigma = 20

k =  \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3

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x - N(150, 20^2)

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Add 17 to both sides

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