Question

How much work is done when a tire’s volume increases from 35. 25 × 10−3 m 3 to 39. 47 × 10−3 m 3 at a pressure of 2. 55 × 105 pa in excess of atmos- pheric pressure? is work done on or by the gas?

Answer 1

The work done for the isobaric process or constant pressure process will be 23.21 kJ.

What is work done for an isobaric process?

The work done for an isobaric process is given by the product of the pressure and the difference between the volume. The formula is given as

WD = P dV

Where P is the pressure (Pascal) and dV is the change in volume (cubic meter).

Work done for the isobaric process or constant pressure process will be

WD = P(V₂ - V₁)

Where V₂ is the final volume and V₁ is the initial volume.

Then we have

WD = 55 x 10⁵ x (39.47 x 10⁻³ - 35.25 x 10⁻³)

WD = 55 x 10⁵ x 4.22 x 10⁻³

WD = 23,210 J

WD = 23.21 kJ

The work done for the isobaric process or constant pressure process will be 23.21 kJ.

More about the work done for an isobaric process link is given below.

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