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MAXImum [283]
3 years ago
10

How to show 268 as a sum of a power of 3 and a square number

Mathematics
2 answers:
Bezzdna [24]3 years ago
4 0

Answer:

\large\boxed{268=3^5+5^2}

Step-by-step explanation:

Consecutive power of number 3:

3^1=3\\3^2=9\\3^3=27\\3^4=81\\3^5=243\\3^6=729>268

268-243=25=5^2

Therefore

268=243+25=3^5+5^2

Let's check the others:

268-81=187\leftarrow\text{it's not a square}\\\\268-27=241\leftarrow\text{it's not a square}\\\\268-9=259\leftarrow\text{it's not a square}\\\\268-3=265\leftarrow\text{it's not a square}\\\\

Therefore we have only one solution.

gizmo_the_mogwai [7]3 years ago
4 0

Answer:

So 268 = 3^x + n^2.

Use trial and error. We know 25 + 243 = 268 so 5^2 + 3^5

Step-by-step explanation:

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Volgvan

Answer:

The rate of change is 1 mile per hour per month

Step-by-step explanation:

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now, we can plug values

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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Shtirlitz [24]

Hello from MrBillDoesMath!

Answer:    75 %

Discussion:

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Thank you,

MrB

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