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Ratling [72]
1 year ago
5

Help please it is timed 40 pts

Mathematics
1 answer:
Stells [14]1 year ago
7 0

Answer:

The answer is D

Step-by-step explanation:

If you use. MAD then all you have to do is multiply add then divide so the 1/4 +1/16 +. 1/64 + 1/256 = 1/3 so round it and. its 1/3 (1/4)

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son4ous [18]

Answer: y=4x−1

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Marisol is making a rectangular wooden frame. She wants the length of the frame to be no more than 12 inches. She has less than
NISA [10]

Answer:

a i the answer

Step-by-step explanation:

l ≤ 12

2l + 2w < 30

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How to solve this problem
Mars2501 [29]

Answer:

3.34166666666666

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Apply The Remainder Theorem, Fundamental Theorem, Rational Root Theorem, Descartes Rule, and Factor Theorem to find the remainde
Over [174]

9514 1404 393

Answer:

  possible rational roots: ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12}

  actual roots: -1, (2 ±4i√2)/3

  no turning points; no local extrema

  end behavior is same-sign as x-value end-behavior

Step-by-step explanation:

The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.

The Rational Root Theorem tells us any rational roots will be of the form ...

  ±{factor of 12}/{factor of 3} = ±{1, 2, 3, 4, 6, 12}/{1, 3}

  = ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12} . . . possible rational roots

Descartes' Rule of Signs tells us the two sign changes mean there will be 0 or 2 positive real roots. Changing signs on the odd-degree terms makes the sign-change count go to 1, so we know there is one negative real root.

The y-intercept is 12. The sum of all coefficients is 22, so f(1) > f(0) and there are no positive real roots in the interval [0, 1]. Synthetic division by x-1 shows the remainder is 22 (which we knew) and all the quotient coefficients are all positive. This means x=0 is an upper bound on the real roots.

The sum of odd-degree coefficients is 3+8=11, equal to the sum of even-degree coefficients, -1+12=11. This means that -1 is a real root. Synthetic division by x+1 shows the remainder is zero (which we knew) and the quotient coefficients alternate signs. This means x=-1 is a lower bound on real roots. The quotient of 3x^2 -4x +12 is a quadratic factor of f(x):

  f(x) = (x +1)(3x^2 -4x +12)

The complex roots of the quadratic can be found using the quadratic formula:

  x = (-(-4) ±√((-4)^2 -4(3)(12)))/(2(3)) = (4 ± √-128)/6

  x = (2 ± 4i√2)/3 . . . . complex roots

__

The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.

4 0
2 years ago
Please help me!! i have no clue what i am doing on this one.
Sonja [21]

Answer:

yr answer is G. 21

<h2>stay safe healthy and happy<u>.</u><u>.</u></h2>

8 0
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