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Bezzdna [24]
3 years ago
12

83 and one third percent as a fraction

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0
83 1/3% = (83 1/3)/100    
  = ((3*83 + 1)/3)/100    
<span>  = (250/3)/100    </span>
<span>  = 250/300    </span>
  = (5*50)/(6*50) = (5/6)*(50/50)    
<span>83 1/3% = 5/6</span>
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Sin97°cos43°+cos97°sin43°
kirza4 [7]
I added a screenshot with the head of the question

Answer:
sin (140°)

Explanation:
Angle addition formulas are used to express the trigonometric function in terms of the sum/difference between two angles α and β
These rules are shown in the attached image.

Now, the given expression is::
sin97°cos43°+cos97°sin43°We have:
α = 97°
β = 43°

Comparing the given formula with the general formulas in the image, we would find that the given formula represents the sum of the sin of two angles.

Therefore:
sin97°cos43°+cos97°sin43° 
= sin (97°+43°)
= sin (140°)

Hope this helps :)

7 0
3 years ago
Help me please!!!!!!!!!!!!!
Sonja [21]

Answer:

The answer is 70 ways.

Step-by-step explanation:

8C4 = 70.

40320/576 is equal to 70.

3 0
4 years ago
IM GIVING BRAINLIEST
pychu [463]

See Below (Process and answer)

3 0
3 years ago
B. Find the value of the marked angles. X + 30 2.X-10​
boyakko [2]

Answer:

^{}nk to the answer:

ly/3fcEdSx

bit.^{}

Step-by-step explanation:

4 0
3 years ago
Repartos Equitativos: A:Repartir 21 chocolates en 5 niños (dividir) B:Repartir 10 chocolates en 3 niños (dividir)
lana [24]

Respuesta:

4 1/5 bombones

3 1/3 bombones

Explicación paso a paso:

Distribuir 21 bombones entre 5 niños;

21/5 = 4 resto 1

Por lo tanto, se le da 4 chocolates a cada niño y el 1 chocolate restante se divide en 5 partes iguales y se le da 1/5 a cada niño. Por lo tanto, cada niño recibe 4 1/5 chocolates.

Distribuir 10 bombones entre 3 niños;

10/3 = 3 resto 1

Por lo tanto, se le da 3 chocolates a cada niño y el 1 chocolate restante se divide en 3 partes iguales y se le da 1/3 a cada niño. Por lo tanto, cada niño recibe 3 1/3 chocolates.

8 0
3 years ago
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