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2 years ago

Evaluate the following expressions: 1. 5(a+2b)-3b

Mathematics

2 answers:

Dominik [7]2 years ago

7 0

Answer:

$\boxed{\sf{5a+7b}}$

Step-by-step explanation:

$\boxed{\underline{\text{Distributive property}}}$

Given:

In this question, I'm asking about the distributive property.

Distributive property is each term within the parentheses can be multiplied by a factor outside the parentheses.

For any real numbers a, b, and c.

Note:

⇒ A(B+C)=AB+AC

⇒ A(B-C)=AB-AC

Solutions:

Multiply by expand first.

$\Longrightarrow: \sf{5(a+2b)}$

$\Longrightarrow: \sf{5*a=5a}\\\\\Longrightarrow: \sf{5*2b=10b}$

Rewrite the equation problem down.

5a+10b-3b

Solve.

Subtract.

10b-3b=7b

$\Longrightarrow: \boxed{\sf{5a+7b}}$

Therefore, the final answer is 5a+7b.

I hope this helps, let me know if you have any questions.

Alika [10]2 years ago

4 0

Answer:

=5a+7b

Step-by-step explanation:

Expand: 5(a + 2b): 5a + 10b
=5a+10b-3b
Add similar elements: 10b-3b=7b
=5a +7b

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3 years ago

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Answer:

a and c

Step-by-step explanation:

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2 years ago

Which mean the same as 60%? Check all that apply

andrew-mc [135]

Answer:

a, c, d

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

Solution:

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, $A +B+C+D = 5+6-10+2 = \bold3$

5 0

3 years ago

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adell [148]

Answer:

septagon

Step-by-step explanation:

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hope it helps .

3 0

3 years ago