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3 years ago

Please help now asap

Mathematics

2 answers:

mestny [16]3 years ago

8 0

(4,26) hope this helps lol!!!!!!

rusak2 [61]3 years ago

3 0

Answer:

(4 ,26)

Step-by-step explanation:

Try to locate the intersection point of the graph of f and the graph of g

which the point with coordinates (4 , 26)

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For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

Simplify the expression below

Brilliant_brown [7]

Answer:

− 4 x + 20

Step-by-step explanation:

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3 years ago

A $52.50 screen door is on sale for $42. Find the percent of discount on the door.

Sindrei [870]

Answer:

20%

Step-by-step explanation:

Given/To Find:

A $52.50 screen door is on

sale for $42. Find the percent

of discount on the door.

Solve:

Formula: Value 1 - Value 2 ÷ Original Value × 100

Hence we have:

52.50 - 42 = 10.5

10.5 ÷ 52.50 = 0.20

0.20 × 100

=20%

Check Answer:

52.50 × 20% = 10.5

52.50 - 10.5 = 42

Hence, the percent of discount on the door is 20%

Kavinsky

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2 years ago

On a trip to the dump Ralph took 56 pounds of garbage. His partner, Kyle, has 64 pounds. How many pounds of garbage did they get

katen-ka-za [31]

Answer:

120 pounds

Step-by-step explanation:

56 + 64 = 120 pounds

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3 years ago

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A triangle has side lengths of 11cm and 9cm. Which could be the value of the third size,20cm or 15cm?

vladimir1956 [14]

If you put in a calculator 11^2+9^2 then square root that it should give you your answer

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