These two cylinders are congruent. cylinder a has a radius of 4 centimeters. cylinder b has a volume of 176π cubic centimeters.
2 answers:
The height of cylinder b is 11 cm.
<h3>How to measure the volume of a cylinder?</h3>The volume of the cylinder is related to the capacity of this geometric figure. Remember that the cylinder or circular cylinder is an elongated and rounded geometric solid.
The formula for the volume of a cylinder is given by:
Where:
- V: volume
- π (Pi): 3
- r: radius
- h: height
In this case, as the cylinders are congruent, both will have the same radius, thus:
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The solutions or roots so-called are really just the x-intercepts, and for a quadratic equation, the vertex is found right half-way between those x-intercepts.
we can get the intercepts by zeroing out "y" or f(x), so let's take a peek at one of those,
so, the x-intercepts or solutions are at 5 and -1, let's take a peek what's the halfway point.
-1----0----1---- 2 ----3-----4------5
well then, now we know the vertex is at x = 2, but, what's the y-coordinate of it anyway?
y = (x - 5)(x + 1)
y = (2 - 5)(2 + 1)
y = (-3)(3)
y = -9
we can get the intercepts by zeroing out "y" or f(x), so let's take a peek at one of those,
so, the x-intercepts or solutions are at 5 and -1, let's take a peek what's the halfway point.
-1----0----1---- 2 ----3-----4------5
well then, now we know the vertex is at x = 2, but, what's the y-coordinate of it anyway?
y = (x - 5)(x + 1)
y = (2 - 5)(2 + 1)
y = (-3)(3)
y = -9
As the problem indicates, degrees of freedom are the number of values that can be independently selected before it is necessary to choose specific values to arrive at the desired result.
The average, on the other hand, results from the sum of a list of values divided by the amount of values in the summed list.
Assume that the mean sought is and consider that the list is composed of a single element
, in that case no random number can be selected, since the mean
must correspond to that number.
If the list were composed of two elements and
, one of the two values could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in
, this given that the formula of the average
.
With three values ,
and
, it is possible to select two freely, since the thirteen must be the one that balances the sum of
, that is
.
Thus, in general, with n values, it is possible to select values freely whose sum must be balanced by the last value so that the whole sum is
.
Answer
In a list of values you can assign
values freely, that is, you have
<em>degrees of freedom.</em>