Answer:
median is 75 and range is 45
Step-by-step explanation:
range is largest number - smallest number so 95-50=45
Median is the medium of all the data. The medium is shown by the middle line in the box portion of the plot.
Answer:
![5\sqrt[4]{x}](https://tex.z-dn.net/?f=5%5Csqrt%5B4%5D%7Bx%7D)
or the fourth answer
Step-by-step explanation:
Apply the rule ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
to rewrite the exponentiation as a radical.
![5\sqrt[4]{x^1}](https://tex.z-dn.net/?f=5%5Csqrt%5B4%5D%7Bx%5E1%7D)
Anything raised to 1 is the base itself.
Answer =
Plz mark me brainliest, hope this helps.
Answer:
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Step-by-step explanation:
9514 1404 393
Answer:
c) 16,500 m³
d) 277,088 mm³
a) V = LWH
b) V = πr²h
Step-by-step explanation:
The relevant volume formulas are ...
- rectangular pyramid: V = 1/3LWH
- cylinder: V = πr²h
- rectangular prism: V = LWH
__
13c. The pyramid formula above tells us the volume is ...
V = 1/3(60 m)(15 m)(55 m) = 16,500 m³
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13d. The cylinder formula above tells us the volume is ...
V = π(35 mm)²(72 mm) ≈ 277,088 mm³ ≈ 277 mL
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14a. The shape appears to be a rectangular prism, so its volume is given by the formula ...
V = LWH . . . . . where L, W, H represent the length, width, and height
__
14b. The volume of a cylinder is given by the formula ...
V = πr²h . . . . . where r, h represent the radius and height (length)
Answer:
![r = \sqrt[3]{\frac{3V}{4 \pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%20%5Cpi%7D%7D)
Step-by-step explanation:
From the formula of volume of a sphere we have to isolate "r" on one side of the equation i.e. we have to make "r" the subject of the equation.
![V=\frac{4}{3} \pi r^{3}\\\\ \text{Multiplying both sides by 3/4 we get}\\\\\frac{3V}{4} = \pi r^{3}\\\\ \text{Dividing both sides by } \pi \\\\ \frac{3V}{4 \pi} = r^{3}\\\\\text{Takeing cube root of both sides}\\\\\sqrt[3]{\frac{3V}{4 \pi}} = r](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E%7B3%7D%5C%5C%5C%5C%20%5Ctext%7BMultiplying%20both%20sides%20by%203%2F4%20we%20get%7D%5C%5C%5C%5C%5Cfrac%7B3V%7D%7B4%7D%20%3D%20%5Cpi%20r%5E%7B3%7D%5C%5C%5C%5C%20%5Ctext%7BDividing%20both%20sides%20by%20%7D%20%5Cpi%20%5C%5C%5C%5C%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%7D%20%3D%20r%5E%7B3%7D%5C%5C%5C%5C%5Ctext%7BTakeing%20cube%20root%20of%20both%20sides%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%20%5Cpi%7D%7D%20%3D%20r)
Therefore:
