Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Answer: 1.091 which is approximately 1 word per second
Step-by-step explanation:
Jack can text 180 words in 2 minutes and 45 seconds. We would convert 2 minutes to seconds
60 seconds = 1 minute
x seconds = 2 minutes
x = 2×60 = 120 seconds
2 minutes 45seconds = 120+45 = 165 seconds
This means Jack can text 180 words in 165 seconds
Let's find his unit rate in texts per second
if jack texts 180 words in 165 seconds
Then jack texts y words in 1 second
165y = 180
y = 180/165= 1.091 words per second
This is approximately 1 word per second
B 12:3 = 4-1=3 C 10- 7=3 And A 2+15x=x=15-2=13
Answer:
HI HI from the UK,
Step-by-step explanation:
For chemistry you would need to get an 84.
For Spanish you would need to get an 82.
Best of luck
