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krok68 [10]
2 years ago
11

What is 5x5 + 5 to the power of 5.

Mathematics
2 answers:
yulyashka [42]2 years ago
7 0

So

  • (5×5+5)⁵
  • (25+5)⁵
  • (30)⁵

a^n=a×a×a×a..n times

  • 30(30)(30)(30)(30)
  • 24300000
-BARSIC- [3]2 years ago
3 0

Answer:

24,300,000

Step-by-step explanation:

Given expression:  (5 \cdot 5 + 5)^5

We can solve this following the order of operations (PEDMAS):

  • Parentheses
  • Exponents
  • Multiplication and Division (from left to right)
  • Addition and Subtraction (from left to right)

We need to carry out that which is in the parentheses first:  5 \cdot 5 + 5

According to the order of operations, we should carry out the multiplication first, followed by the addition:

\implies 5 \cdot 5+5=25+5=30

Therefore,

(5 \cdot 5 + 5)^5=(30)^5

Finally, we carry out the exponent:

\begin{aligned}\implies 30^5 &=30 \cdot 30 \cdot 30 \cdot 30 \cdot 30\\ & =24,300,000\end{aligned}

Therefore,

(5 \cdot 5 + 5)^5=24,300,000

-------------------------------------------------------------------------------------------

Alternatively, if the expression is 5 \cdot 5 + 5^5

We would carry out the exponent first:

\begin{aligned}\implies 5 \cdot 5 + 5^5 &=5 \cdot 5+(5 \cdot 5 \cdot 5 \cdot 5 \cdot 5)\\ & =5 \cdot 5+3125\end{aligned}

Then the multiplication:

\implies 5 \cdot 5+3125=25+3125

And finally the addition:

\implies 25+3125=3150

Therefore,

5 \cdot 5 + 5^5=3150

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Answer:

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Step-by-step explanation:

y =  {x}^{2}  + x + 2

We can covert the standard form into the vertex form by either using the formula, completing the square or with calculus.

y = a(x - h)^{2}  + k

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<u>Vertex</u><u> </u><u>—</u><u> </u><u>Formula</u>

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y =  {x}^{2}  +  x + 2

Differentiate the following equation. We can use the dy/dx symbol instead of f'(x) or y'

f'(x) = (2 \times 1 {x}^{2 - 1} ) + (1 \times  {x}^{1 - 1} ) + 0

Any constants that are differentiated will automatically become 0.

f'(x) = 2 {x}+ 1

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