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Triss [41]
3 years ago
15

X = 1/2at^2 Solve for t. 1. 2. 3. 4.

Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0
Lets get started :)

We need to isolate t from x = \frac{1}{2}at²

Take 2 to the left-hand side { Do multiplication since you see division }
2x = at²

Take a to the left-hand side { Do division since you see multiplication }
\frac{2x}{a} = t² 

Take square root since t is to the power of 2
\sqrt{ \frac{2x}{a} } = t 
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Answer:

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Step-by-step explanation:

27a + 1/3 * b = 4

Subtract the term with b from both sides.

27a = 4 - 1/3 *b

Divide both sides by 27.

a = 4/27 - 1/81 * b

a = 4/27 - b/81

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Last one!! I need the steps please! Will mark brainliest!
hoa [83]

Answer:

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Step-by-step explanation:

Given function:

h(t)=-6t^2+24t

where:

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  • t = times (in seconds)

Rewrite in the form h(t)=a(t-h)^2+k

The quickest way to do this is to expand h(t)=a(t-h)^2+k and compare coefficients with the original function.

\begin{aligned}h(t)& =a(t-h)^2+k\\ & = at^2-2aht+ah^2+k\end{aligned}

Comparing coefficients with h(t)=-6t^2+24t

\begin{aligned}\implies at^2& =-6t^2\\ a &=-6\end{aligned}

\begin{aligned}\implies -2aht & =24t\\ -2(-6)ht& =24t\\ 12ht & = 24t\\ 12h & = 24\\ h & = 2\end{aligned}

\begin{aligned}\implies ah^2+k & = 0\\(-6)(2)^2+k &=0\\ -24+k & =0\\ k &=24 \end{aligned}

Therefore, substituting the found values into the equation:

h(t)=-6(t-2)^2+24

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then factor it

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Answer:

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