Question

PLEASE HELP ME! Find the 10th term of the geometric sequence that has a1 = 400 and A2 = 200.​

Answer 1

Answer:

I believe the answer is 0.7813

Step-by-step explanation:

Find the difference between 400 and 200, as they are first and second terms. This is going to be 0.5 since it is being divided.

The formula is: a∨n=a∨1(r)^(n-1)

n= the number of the sequence you are looking for

r=0.5

a∨1=400

a∨2=200

400(0.5)^(10-1)