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musickatia [10]
2 years ago
10

What is the solution to the system of equations?

Mathematics
1 answer:
jek_recluse [69]2 years ago
4 0

Answer: (8, -4)

Step-by-step explanation:

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The width is 1.5.
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Brainliest would be nice
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Write an equation for the following problem.
kakasveta [241]

Answer:  Aaron was at the sitter for 5 hours

Step-by-step explanation:

12x + 10 = 58

the 12x is for each hour after the first hour and the 10 is the first hour

-10 from each side

12x = 48

/12

x = 4

4 additional hours plus the original hour

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2 years ago
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Write the equation of a line perpendicular to 3x+2y=6 through (2,-1).
iren [92.7K]
Rearrange: 2y = 6 -3x
2y = - 3x + 6
y = -1.5x + 3
Now, substitute, perpendicular lines have the same gradient so:
-1 = -1.5 (2) + c
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equation for new line: y = 1.5x + 2
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2 years ago
An experimenter is studying the effects of temperature, pressure, and type of catalyst on yield from a certain chemical reaction
irga5000 [103]

Answer:

90

12

0.0154

Step-by-step explanation:

a) #Possible experimental run=#Temp x #pres x #cat=3x5x6=90

b) #Possible experimental run=(Temp. lowest) x 2.pres x #cat=1x2x6=12

c) C="different catalyst is used on each run"

In the first, I can choice 6 of 6 catalysts, in the second 5 of 6,...

then: P(C) = 6/6 x 5/6 x 4/6 x 3/6 x 2/6 x 1/6 = 5/324 = 0.0154

3 0
3 years ago
rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t
ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

y=h+ut+\frac{1}{2}at^2

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

a=g=-9.8 m/s^2 is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

11=23+27t-4.9t^2\\4.9t^2-27t-12=0

This is a second-order equation, which has solutions:

t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}

So

t_1 = -0.41 s

t_2=5.92 s

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0
3 years ago
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