I do believe that would be x=6 and x=-8
Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
This doesn't answer it completely but you have to complete the square. I don't know the answer but there are plenty of videos on how to complete the square online. Hope I could help and sorry if I didn't <span />
Answer: See below
Step-by-step explanation:
<u>To find the factor,</u>
f(x) = 0

<u>So,</u>
x = 0 multiplicity 2
x = -6 multiplicity 1
x = 6 multiplicity 1
For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis
<u>Therefore,</u>
x = 0 multiplicty 2, Touch
x = -6 multiplicty 1, Cross
x = 6 multiplicty 1, Cross
Answer:
b
Step-by-step explanation: