When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
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We know that
When two chords intersect each other inside a circle, the products of their segments are equal (Intersecting Chord Theorem)
so
8*18=x*6--------> x=8*18/6-----> x=24
the answer is
24
To solve this problem you must apply a theorem called: Intersecting secant theorem. The proccedure is shown below:
1) For the figure shown on the left:
(5)(x+5)=(6)(4+6)
5x+25=60
5x=60-25
x=35/5
x=7
2) For the figure shown on the right:
(3)(3+5)=(4)(x+4)
24=4x+16
24-16=4x
8=4x
8/4=x
x=2
The slope is 2 units down for 9 units over, so is -2/9. The y-intercept is 4.
In slope-intercept form the equation of the line is
y = (-2/9)x +4
Answer:
Area covered by beam = 530 mi² (Approx.)
Step-by-step explanation:
Given:
Radius = 15 mi
Arc angle = 270°
Find:
Area covered by beam
Computation:
Area of sector = [θ/360][π][r²]
Area covered by beam = [270/360][22/7][15²]
Area covered by beam = [0.75][3.1428][225]
Area covered by beam = 530 mi² (Approx.)