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Serjik [45]
2 years ago
7

You have a computer that has four DDR2 memory slots. Currently, there are two 512 MB memory modules installed. You check the mot

herboard documentation and find that the system has a 4 GB memory limitation. You want to add more memory to this system. By adding new memory modules, and without replacing the existing memory modules, what is the maximum total amount of usable RAM you can have in this system
Computers and Technology
1 answer:
nadya68 [22]2 years ago
6 0

Answer:

2048 MB / 2 GB.

Explanation:

Without removing the other modules you can add two more 512 MB modules for a total of 2048 MB.

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In the computer science industry, the process of finding and removing errors from computer hardware or software is known as
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Debugging i think it is
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3 years ago
In a(n) ____ design, the remote user's keystrokes are transmitted to the mainframe, which responds by sending screen output back
Harrizon [31]

Answer:

I think it would be centralized

4 0
3 years ago
We assume that ABC Corporation has two business offices. These offices are in the cities of Orlando and Miami. These cities are
murzikaleks [220]

Answer:

The following are the answer to the given points:

Explanation:

In point (a):

Calculating the long-distance call cost:

= 4 \times 5 \times 0.40 \\= 20 \times 0.40\\= 8

Calculating the local call cost:

= 10 \times 3  \times 0.05\\ = 30 \times 0.05\\= 1.5

Calculating the overall cost of PSTN:

= 25 + (4 \times 5 \times 0.40) + (10 \times 3 \times 0.05) + 2000 + 275 \\= 25 + 8 + 1.5 + 2000 + 275 \\=   2309.5

In point (b):

Calculating the call rate per second and the average arrival rate:

\to (\lambda) = 0.2

The call average length:

\to (T_s) = - 8  \\\\ = (8  \times 60) \ seconds \\\\ = 480 \ seconds  

The complete agent number:

\to  (m) = 9

The strength of traffic:

\to u = \lambda \times  T_s  \\\\  =   (0.2  \times 480) \\\\ = 96    

The occupancy of the agent:

\to  p = \frac{u}{m}  \\\\

      = \frac{96}{9}  \\ \\= 10.66  

Calculation of obtained:

= \frac{(\frac{um}{m!})}{(\frac{um}{m!})} + (1-p) \sum {m-1} _{k=0}  \ \frac{uk}{k!}

We get = 0.329 to substitute values.  

In point (c):

The rate of blocking = 5 \%

average call time (T_s) = 480 \ seconds

                                    = 0.05 \times  480 \ seconds \\  = 24 \ second

In point (d):

Calculating the number of link, which is required:  

= \frac{275}{5} \\\\ =55

In point (e):

Calculating the Line Number:

= \frac{275}{5} \\\\ =55

PSTN line number:

=  (\frac{2000}{55}) \\\\ = 36.3636\\\\= 37

In point (f):

The gross design expense = $ 2309. 5

5 0
4 years ago
Which of the following scenarios describes an IT professional using the Internet and computer system access in an unprofessional
pantera1 [17]

Answer:

All of the above

Explanation:

6 0
3 years ago
Refer to the method f:
Goshia [24]
<h2>This function will land up in infinite function call</h2>

Explanation:

first time when the function gets invoked,

f(6,8), so k=6 & n=8, inside the function it checks k==n, ie. 6==8, returns false, then one more if is available, so 6>8 is check for , once again it is false and else loop is executed, the function is called recursively using f(k-n,n), that is f(6-8,8), it means f(-2,8) is passed.

Second time,

if(-2==8) is false, so if(-2>8) is again false and function f(-10, 8) is called

if(-10==8) is false, so if(-10>8) is again false and function f(-18,8) is called

if(-18==8) is false, so if(-18>8) is again false and function f(-26,8) is called

So this goes recursively and ends in an infinite function call.

5 0
4 years ago
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