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Rainbow [258]
3 years ago
9

How do you find the perimeter of a triangle using one side length and two angles of 60 degrees

Mathematics
1 answer:
Licemer1 [7]3 years ago
8 0
Give me a picture of the problem and i will solve it
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The circumference of a circle is 407 cm. Find the diameter, the radius, the length of an arc of 100°, and the area of a sector w
iogann1982 [59]

Answer: 407cm =

100° =

100° =

I hope this helps :)

4 0
2 years ago
At the track practice, Sam practiced running the hurdles for 1 hour and 25 minutes. Then he practiced the high jump for 20 minut
blagie [28]

Answer:

Practice started at 1:55 pm.

Step-by-step explanation:

6 0
2 years ago
Multiply 2(x+3)/x(x-1)*4x(x+2)/10(x+3)
KIM [24]

Answer:

The expression simplifies to \frac{4(x+2)}{5(x-1)}.

Step-by-step explanation:

The expression

\frac{2(x+3)}{x(x-1)} *\frac{4x(x+2)}{10(x+3)}

can be rearranged and written as

\frac{8x(x+3)(x+2)}{10x(x-1)(x+3)}.

In this form the (x+3) terms in the numerator and in the denominator cancel to give

\frac{8x(x+2)}{10x(x-1)}.

The x's are present both in the numerator and in the denominator, so they also cancel, and the fraction \frac{8}{10} simplifies to \frac{4}{5}, so finally our expression becomes:

\boxed{\frac{4(x+2)}{5(x-1)}}

Which is our answer:)

6 0
2 years ago
100 POINTS plz help Chuck drops a rock from a height of 70 m. How long will it take the rock to hit the ground?
lord [1]

Answer:

3.8

Step-by-step explanation:

We are going to plug in the values of the equation, so h(t)=-4.9^2+v0t+h0 will

now be h(t)=-4.9^2+0+70

Now we will find the a b and c of the equation,  a=-4.9 b=0 c=70

Now we must find the discriminant of the equation,  which the equation for that is D=b^2+(-4)(a)(c)

So D=1,372

Now we use the quadratic formula (see picture below for finished product)

4 0
3 years ago
Read 2 more answers
WRITING LINE AR INEQUALITIES Nancy works at Love at First Bite bakery where she decorates cakes and cupcakes. It takes her an av
ozzi

Answer:

32

Step-by-step explanation:

6 0
2 years ago
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