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spin [16.1K]
3 years ago
15

Can someone Help plz!!

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0
No clue fubriffnirfbiddb
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2 years ago
find two positive even consecutive integers such that a square of the smaller integer is 10 more than the larger integer
nalin [4]

Answer:

the two positive consecutive integers are 4 and 6.

Step-by-step explanation:

Let the smaller integer be s; then s^2 = (s + 2) + 10.

Simplifying, s^2 - s - 2 - 10 = 0, or

s^2 - s - 12 = 0.

Solve this by factoring:  (s - 4)(s + 3) = 0.

Then s = 4 and s = -3.

If the first even integer is 4, the next is 6.  We omit s = -3 because it's not even.

The smaller integer is 4.  Does this satisfy the equation s^2 = (s + 2) + 10?

4^2 = (4 + 2) + 10  True or False?

16 = 6 + 10 = 16.

True.

So the two positive consecutive integers are 4 and 6.

6 0
3 years ago
5 : 2 : 11 =.... : 6 : ....
lubasha [3.4K]
5:2:11=15:6:33
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2 years ago
_ _ 4 <br> +68_ <br> = - 327 <br> find missing numbers
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Step-by-step explanation:

I just played with numbers because I learned this when I was 4 but forgot the concept, but now I’m 12 in 11th grade.

4 0
1 year ago
Read 2 more answers
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