Four thousand one hundred eighty
(x-3)^2=(3x+10)*(x-3) so to solve this u can simply take (x-3) over to the other side so it will; look like this
(x-3)^2/(x-3)=3x+10
then it will be x-3=3x+10
-2x=13
x=-13/2 which is -6.5
Answer:
x-axis: (3, 0)
y-axis: (0, 16)
Quadrant 1: (36.7, 3.9)
Quadrant 2: (-1, 2)
Quadrant 3: (-5/8, -5 1/3)
Quadrant 4: (2, -12)
Step-by-step explanation:
x-axis: when y = 0 ⇒ (3, 0)
y-axis: when x = 0 ⇒ (0, 16)
Quadrant 1: when x > 0 and y > 0 ⇒ (36.7, 3.9)
Quadrant 2: when x < 0 and y > 0 ⇒ (-1, 2)
Quadrant 3: when x < 0 and y < 0 ⇒ (-5/8, -5 1/3)
Quadrant 4: when x > 0 and y < 0 ⇒ (2, -12)
Answer:
C
Step-by-step explanation:
This is actually a combination problem as we are trying to select groups of 5 from the 15 qualified trainees.
To do this, we use the combinatorial approach. This is done by using the formula 15C3 = 15!/(15-3)!3!
This gives a value of 455
Answer:
2
Step-by-step explanation:-3 (4 - 7) + (2 x 5 - 17)
-3 (4 - 7) + (10 - 17)
-3 x (-3) + (-7)
9 + (-7)
9 - 7
=2
